Help with Time/space complexity. Would the time complexity be O(n^2) or O(n*m) ? def longestCommonPrefix(self, strs: List[str]) -> str:def lcp(strs):if strs ==24 v:5returnif len(strs)return strs[0]6 v== 1:78.strs[0]prefix =prefixlength9.10len(prefix)%3D1112 vfor word in strs[1:]:while prefix != word[0:prefixLength]: # flower != flowprefix = prefix[0:(prefixLength-1)] #floweprefixlength13 v14%3D15-= 11617 vif prefixLength== 0:18return19return prefix20

If n is the number of strings and m is the length of the largest string.

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Help with Time/space complexity. Would the time complexity be O(n^2) or O(n*m) ?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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