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hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie

hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie 

Example (page 181) If J = - (2 cos 0 a, + sin 0 a,) A/m², calculate the current passing through (a) A hemispherical shell of radius 20 cm (b) A spherical shell of radius 10 cm Example (page 181) Solution: 1- JJ. ds. where dS = r²sin 9 do de a, in this case. w/22m (a) I = = [2 / 2 cos 0 r² sine døp de 0=0-6=0 ra/2 -32= *sindsin). sin 0 d( sin 0) 6=0 47 sin² 0 0.2 2 10 = = 107 = 31.4 A Tr=0.2
Transcribed Image Text:Example (page 181) If J = - (2 cos 0 a, + sin 0 a,) A/m², calculate the current passing through (a) A hemispherical shell of radius 20 cm (b) A spherical shell of radius 10 cm Example (page 181) Solution: 1- JJ. ds. where dS = r²sin 9 do de a, in this case. w/22m (a) I = = [2 / 2 cos 0 r² sine døp de 0=0-6=0 ra/2 -32= *sindsin). sin 0 d( sin 0) 6=0 47 sin² 0 0.2 2 10 = = 107 = 31.4 A Tr=0.2
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