Hi i am looking for an answer to question 2 please PRELAB EXERCISES'+RC=VCViFigure 1. The diode peak detector circuit.1. The input voltage in the diode peak detector is al10V amplitude, cosinusoidal voltage signalwith a frequency of 1kHz. Assume that the capacitor C = 10µF. Calculate the value of theresistor, R, to give a circuit time constant of 2ms when the diode operates in reverse bias.2. In your laboratory notebook, sketch the expected capacitor voltage, vɖt), over two completeperiods of the input voltage, v, (f). Hint: see EE2013 Lecture 3.3. For the input voltage parameters in Pre-lab exercise 1, calculate the first positive time (ton,where ton> 0) when the diode turns on. To solve for ton, you will need to solve an implicitequation which equates a first-order time-decaying voltage to a sinusoidal input voltage. Theeasiest way to accomplish this is to numerically test time-points (e.g., using Matlab, Excel oryour calculator and a sheet of paper) that you expect to be close to the 'cross-over’ time(which will be less that 1 period) and see which time-point most closely approximates theequation. Bear in mind that ton is the first non-zero time-point when the decaying capacitorvoltage and the cosinusoidal input intersect.4. What is the corresponding capacitor voltage at the time; i.e., vɖton). You can find this usingeither the input signal or the capacitor voltage.5. As a design task, you have been requested to decrease the ripple voltage in the capacitor (i.e.,the difference between v(ton) and the input amplitude) by adjusing the value of the resistor,R. Should you increase or decrease R to accomplish your task?

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Answered: Hi i am looking for an answer to…

Engineering

Electrical Engineering

Hi i am looking for an answer to question 2 please

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter59: Motor Startup And Troubleshooting Basics

Section: Chapter Questions

Problem 12SQ: How is a solid-state diode tested? Explain.

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How is a solid-state diode tested? Explain.
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