Home Work 5.6-2 The number of cracks in a section of interstate highway that are significant enough to require repair is assumed to follow a Poisson distribution with a mean of two cracks per mile. (a) What is the probability that there are no cracks that require repair in 5 miles of highway? Ans. P(0; 10) = 4.54 x 10-5 (b) What is the probability that at least one crack requires repair in half mile of highway? Ans. P(X 2 1,1) = 0.6321

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Chapter1: Functions And Models
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Home Work 5.6-2
The number of cracks in a section of interstate highway that are significant
enough to require repair is assumed to follow a Poisson distribution with a mean
of two cracks per mile.
(a) What is the probability that there are no cracks that require repair in 5 miles
of highway? Ans. P(0; 10) = 4.54 x 10-5
(b) What is the probability that at least one crack requires repair in half mile of
highway? Ans. P(X 2 1,1) = 0.6321
Transcribed Image Text:Home Work 5.6-2 The number of cracks in a section of interstate highway that are significant enough to require repair is assumed to follow a Poisson distribution with a mean of two cracks per mile. (a) What is the probability that there are no cracks that require repair in 5 miles of highway? Ans. P(0; 10) = 4.54 x 10-5 (b) What is the probability that at least one crack requires repair in half mile of highway? Ans. P(X 2 1,1) = 0.6321
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