How did the negative sign appear? To prove cos (iz) = cos h (z) = cos since et+e¬* eix +e-ix cos h (x) and cos (x) = 2 2 LHS=cos (iz) e(12) +e-i(iz) -e-+e? 2 2 RHS=cos h (z) : e+e=? Since, LHS=RHS.
How did the negative sign appear? To prove cos (iz) = cos h (z) = cos since et+e¬* eix +e-ix cos h (x) and cos (x) = 2 2 LHS=cos (iz) e(12) +e-i(iz) -e-+e? 2 2 RHS=cos h (z) : e+e=? Since, LHS=RHS.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 44E
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