How did the negative sign appear? To prove cos (iz) = cos h (z) = cos since et+e¬* eix +e-ix cos h (x) and cos (x) = 2 2 LHS=cos (iz) e(12) +e-i(iz) -e-+e? 2 2 RHS=cos h (z) : e+e=? Since, LHS=RHS.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 44E
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How did the negative
sign appear?
To prove cos (iz)
= cos h (z)
since
cos h (x) :
e+e-*
and cos (x)
eix +e-ix
LHS=cos (iz) :
eiliz) +e¬i(iz)
-e-?+e?
2
e+e-z
RHS=cos h (z)
2
Since, LHS=RHS.
It can be proved that
cos (iz) = cos h (z)
Transcribed Image Text:How did the negative sign appear? To prove cos (iz) = cos h (z) since cos h (x) : e+e-* and cos (x) eix +e-ix LHS=cos (iz) : eiliz) +e¬i(iz) -e-?+e? 2 e+e-z RHS=cos h (z) 2 Since, LHS=RHS. It can be proved that cos (iz) = cos h (z)
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