How did you get the (2n+1)(2n-1)? I just don't know where the (2n+1) came from. thanks in advance

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How did you get the (2n+1)(2n-1)? I just don't know where the (2n+1) came from.

thanks in advance!

не
Un=
lim unti
na
=
1.3.5
lim
844
(5")n!
lim
5 no
} +
= lim (2n+1)
n=∞
-(2n-1)
1.3.5-- (2n-1) (2n+1)
(5+1)(n+1)!
(5)(n+1)
(1 + A₂)
1 + 1 > 1
lim
n+∞ 1+1/n
It sh
·x (5^) n!
1.3-5--- - (2n-1)
Hence the series is
[divergen+]
Transcribed Image Text:не Un= lim unti na = 1.3.5 lim 844 (5")n! lim 5 no } + = lim (2n+1) n=∞ -(2n-1) 1.3.5-- (2n-1) (2n+1) (5+1)(n+1)! (5)(n+1) (1 + A₂) 1 + 1 > 1 lim n+∞ 1+1/n It sh ·x (5^) n! 1.3-5--- - (2n-1) Hence the series is [divergen+]
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