How do I find the slope or if my graph is correct

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter15: Oscillations
Section: Chapter Questions
Problem 60AP: A mass is placed on a frictionless, horizontal table. A spring (k=100N/m) , which can be stretched...
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How do I find the slope or if my graph is correct 

Figure 4. How to correctly measure the position of the bottom of the spring when the
weight hanger carries the required added masses.
M₁ (g) =
MSW
(8)
50
100
150
200
250
Table # 1: Determination of the spring constant K
X₁ (cm) = _, 2
MT= Mh+Msw
MT
(8)
MT
(kg)
8 = 9.80 m/s²
F=W=MT g
FK
(N)
0
6.6.5. 0.066.5
0.6517
1/6:52 0.116.5 1.1417
xf
(cm)
13.3
166.5 0.166.5 1.63/7 4.9
44
216.2 0.2165 212/7
266.55 02. 266.5
6.9
x = xf- Xo
10.2
2.6/17 8
X
(cm)
x
(m)
0
Average force constant Kavg
Force constant Ktren from the slope of the trendline in the graph
% relative difference between Kavg and Ktren
Mh: Mass of the weight hanger
Msw: Mass of added slotted weights
Mr: Total Mass
W: Weight of hanger plus slotted weights
aq
K =
F(N)
x(m)
0.2 0.1
6517
2.5ch 0.025 45.068
You 0.09 40,7925
0:055 38.576 3 6 3 6 4
36.9736 LLL
35.7829 n/m
55
7.2 0.072
K
(N/m)
xo: Position of the spring's bottom (unstretched)
xf: Position of the spring's bottom (stretched)
x: Elongation of the spring
K: Force constant of the spring
Transcribed Image Text:Figure 4. How to correctly measure the position of the bottom of the spring when the weight hanger carries the required added masses. M₁ (g) = MSW (8) 50 100 150 200 250 Table # 1: Determination of the spring constant K X₁ (cm) = _, 2 MT= Mh+Msw MT (8) MT (kg) 8 = 9.80 m/s² F=W=MT g FK (N) 0 6.6.5. 0.066.5 0.6517 1/6:52 0.116.5 1.1417 xf (cm) 13.3 166.5 0.166.5 1.63/7 4.9 44 216.2 0.2165 212/7 266.55 02. 266.5 6.9 x = xf- Xo 10.2 2.6/17 8 X (cm) x (m) 0 Average force constant Kavg Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mh: Mass of the weight hanger Msw: Mass of added slotted weights Mr: Total Mass W: Weight of hanger plus slotted weights aq K = F(N) x(m) 0.2 0.1 6517 2.5ch 0.025 45.068 You 0.09 40,7925 0:055 38.576 3 6 3 6 4 36.9736 LLL 35.7829 n/m 55 7.2 0.072 K (N/m) xo: Position of the spring's bottom (unstretched) xf: Position of the spring's bottom (stretched) x: Elongation of the spring K: Force constant of the spring
g when the
F(N)
x(m)
(7)
A
7
8
25
H
I'm
G
2.607
2.1217
116317
1,1417
0.65/7
Figure.
Please show here the calculation of the slope.
Slope =
0.025 004 0055 0.072 00
x
ソク
PAH
EL
ΞΕΙ
1
й
E
JOIN
Transcribed Image Text:g when the F(N) x(m) (7) A 7 8 25 H I'm G 2.607 2.1217 116317 1,1417 0.65/7 Figure. Please show here the calculation of the slope. Slope = 0.025 004 0055 0.072 00 x ソク PAH EL ΞΕΙ 1 й E JOIN
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