In this experiment, a tennis ball is released from a certain height. While the ball falls down, time of release (t;) and time when the ball touches the ground (tr) are recorded using a stopwatch and slow motion video. The difference At = tr-ti is the time interval during the fall. For the first experiment (available with video), t=17.31s and tr= 17.94s, yielding At = 17.94s - 17.31s = 0.63s. At values are listed below for 5 different repeats of the experiment using the same height. Experiment No At (s) 0.63s 2 0.64s 3 0.62s 4 0.65s 5 0.63s ANALYSIS: 1. Calculate the release height (initial height) of the ball for each of the five experiments. (Show calculation. Include the formula, units used in your calculation)

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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DATA:
In this experiment, a tennis ball is released from a certain height. While the ball falls down, time of
release (t;) and time when the ball touches the ground (tf) are recorded using a stopwatch and slow
motion video. The difference At = tr-ti is the time interval during the fall. For the first experiment
(available with video), t=17.31s and tr= 17.94s, yielding At = 17.94s - 17.31s = 0.63s.
At values are listed below for 5 different repeats of the experiment using the same height.
Experiment No
Δt ( s)
0.63s
2
0.64s
3
0.62s
4
0.65s
0.63s
ANALYSIS:
1. Calculate the release height (initial height) of the ball for each of the five experiments.
(Show calculation. Include the formula, units used in your calculation)
Calculations:
2. Calculate the average of release heights from the five experiments. (Show calculation.
Include units)
Calculations:
2
3. Calculate the final velocity of the ball when it hits the ground.
(Show calculation. Include the formula, units used in your calculation)
Calculations:
Transcribed Image Text:DATA: In this experiment, a tennis ball is released from a certain height. While the ball falls down, time of release (t;) and time when the ball touches the ground (tf) are recorded using a stopwatch and slow motion video. The difference At = tr-ti is the time interval during the fall. For the first experiment (available with video), t=17.31s and tr= 17.94s, yielding At = 17.94s - 17.31s = 0.63s. At values are listed below for 5 different repeats of the experiment using the same height. Experiment No Δt ( s) 0.63s 2 0.64s 3 0.62s 4 0.65s 0.63s ANALYSIS: 1. Calculate the release height (initial height) of the ball for each of the five experiments. (Show calculation. Include the formula, units used in your calculation) Calculations: 2. Calculate the average of release heights from the five experiments. (Show calculation. Include units) Calculations: 2 3. Calculate the final velocity of the ball when it hits the ground. (Show calculation. Include the formula, units used in your calculation) Calculations:
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