How is Ic = 0.3682 calculated through ratio and proportion? Show complete solution and neat handwriting. Pressure increase below a rectangular area byBoussinesq, directly at the centerqolc__%o=pressure at the base of footing1875 kNAo =P= -=150 kPaA2.5m x 5mDetermine Ic from Table 6.5L3.25= 2.6m1В= 22.5В2.522Note: z is measured from base of footing up to center of clay layer.Table 6.5 Variation of l̟ with m, and nBy Ratio & Proportion, Ic = 0.3682%3DAo = q,Ic = 150(0.3682) = 55.23 kPan;123Thus, Consolidation Settlement1.800.3880.5340.5732.5m(0.32) log-52.83 + 55.232.000.3360.4810.5253.000.1790.2930.3481+ 0.852.834.000.1080.1900.241dc == 0.138m— 138 тт67

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How is Ic = 0.3682 calculated through ratio and proportion? Show complete solution and neat handwriting.

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter17: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 17.16CTP

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How is Ic = 0.3682 calculated through ratio and proportion? Show complete solution and neat handwriting.

Pressure increase below a rectangular area by
Boussinesq, directly at the center
qolc__%o=pressure at the base of footing
1875 kN
Ao =
P
= -=
150 kPa
A
2.5m x 5m
Determine Ic from Table 6.5
L
3.25
= 2.6
m1
В
= 2
2.5
В
2.5
2
2
Note: z is measured from base of footing up to center of clay layer.
Table 6.5 Variation of l̟ with m, and n
By Ratio & Proportion, Ic = 0.3682
%3D
Ao = q,Ic = 150(0.3682) = 55.23 kPa
n;
1
2
3
Thus, Consolidation Settlement
1.80
0.388
0.534
0.573
2.5m
(0.32) log-
52.83 + 55.23
2.00
0.336
0.481
0.525
3.00
0.179
0.293
0.348
1+ 0.8
52.83
4.00
0.108
0.190
0.241
dc =
= 0.138m
— 138 тт
67

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