How many different choices can be made from 5 red beads, 4 gold beads and 8 blue beads if at least one bead is to be chosen for making a bracelet? O 269 O 270 O 281 O 300

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section: Chapter Questions
Problem 40CT: There are 10 applicants for three sales positions at a department store. All of the applicants are...
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How many different choices can be
made from 5 red beads, 4 gold beads
and 8 blue beads if at least one bead is
to be chosen for making a bracelet? *
269
270
281
300
There are 12 people in a dinner
gathering. In how many ways can the
host (one of the 12) arrange his guests
around the dining table if 3 people
insist on sitting beside each other?
*
2, 177, 280
20, 052, 880
32,659, 200
39, 916, 800
Transcribed Image Text:How many different choices can be made from 5 red beads, 4 gold beads and 8 blue beads if at least one bead is to be chosen for making a bracelet? * 269 270 281 300 There are 12 people in a dinner gathering. In how many ways can the host (one of the 12) arrange his guests around the dining table if 3 people insist on sitting beside each other? * 2, 177, 280 20, 052, 880 32,659, 200 39, 916, 800
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