How many grams of LizN can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li (s) + N2(g) --> 2 LizN (s) 20.3 g LigN Oa. Ob. 18.3 g LigN Oc 58.3 g LigN Od 61.0 g LigN Oe 15.1 g LigN

Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter11: Solutions And Colloids
Section: Chapter Questions
Problem 50E: A sample of an organic compound (a nonelectrolyte) weighing 1.35 g lowered the freezing point of...
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QUESTION 2
How many grams of LigN can be formed from 1.75 moles of Li? Assume an excess of nitrogen.
6 Li (s) + N2(g)
--> 2 LizN (s)
20.3 g LigN
a.
Ob. 18.3 g LizN
OC 58.3 g LizN
Od.61.0 g LigN
Oe. 15.1 g LigN
Transcribed Image Text:QUESTION 2 How many grams of LigN can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li (s) + N2(g) --> 2 LizN (s) 20.3 g LigN a. Ob. 18.3 g LizN OC 58.3 g LizN Od.61.0 g LigN Oe. 15.1 g LigN
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9781938168390
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Publisher:
OpenStax