How many kilo calories (kcal) required to change 1 kg of 0°C ice to 0°C are water?

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Chapter1: Temperature And Heat
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How many kilo calories (kcal) are required to change 1 kg of 0°C ice to 0°C
water?
Transcribed Image Text:How many kilo calories (kcal) are required to change 1 kg of 0°C ice to 0°C water?
The quantity of heat Q that changes the temperature AT of a mass m of a
substance is given by Q
= cm AT, where c is the specific heat capacity of
the substance (c = 1 cal/g°C = 4.2 J/g°C for water). The above only applies
if the substance is not changing phase however.
During phase transitions the heat Q absorbed by a substance will go into
changing the phase of the substance (e.g melting or vaporizing) and not into
changing its temperature, thus during phase transitions the temperature of
the substance will not change (see figure below). The quantity of heat Q
that changes the phase of a mass m is Q
mL, where L is the latent
heat of fusion or vaporization of the substance. For water the heat of fusion
80 cal/g = 335 J/g, and the heat of vaporization is Lvaporization
is L fusion
540 cal/g = 2260 J
100°-
Vaporizing
Ice
Melting
0°-
80 cal ; 100 cal :
-50°
540 cal
(335 J) (419 J)
(2260 J)
Heat
Temperature in C°
Water
Steam
Transcribed Image Text:The quantity of heat Q that changes the temperature AT of a mass m of a substance is given by Q = cm AT, where c is the specific heat capacity of the substance (c = 1 cal/g°C = 4.2 J/g°C for water). The above only applies if the substance is not changing phase however. During phase transitions the heat Q absorbed by a substance will go into changing the phase of the substance (e.g melting or vaporizing) and not into changing its temperature, thus during phase transitions the temperature of the substance will not change (see figure below). The quantity of heat Q that changes the phase of a mass m is Q mL, where L is the latent heat of fusion or vaporization of the substance. For water the heat of fusion 80 cal/g = 335 J/g, and the heat of vaporization is Lvaporization is L fusion 540 cal/g = 2260 J 100°- Vaporizing Ice Melting 0°- 80 cal ; 100 cal : -50° 540 cal (335 J) (419 J) (2260 J) Heat Temperature in C° Water Steam
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