How many kilocalories are required to produce 2.815 mol of aluminum? Here is the equation for aluminum oxide conversion to aluminum 2Al2O3(s)→4Al(s)+3O2(g)2Al2O3(s)→4Al(s)+3O2(g),   ΔHΔH = +801.0 kcalkcal

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
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How many kilocalories are required to produce 2.815 mol of aluminum?

Here is the equation for aluminum oxide conversion to aluminum

2Al2O3(s)→4Al(s)+3O2(g)2Al2O3(s)→4Al(s)+3O2(g),  
ΔHΔH = +801.0 kcalkcal

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How many kilocalories are required to produce 61.91 gg of aluminum?

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