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- A 19.51 ݃ sample of impure methylamine, which contains 72.58% (by mass) of CH3NH2 , isreacted with 30.81 ݃ of pure oxygen gas:4CHଷNHଶ(g) + 9Oଶ(g) ⟶ 4COଶ(g) + 10HଶO(ℓ) + 2Nଶ(g) In another experiment, this impure methylamine was used as follows: An unknown mass of the impure compound is dissolved in enough water to make 500.0 ݉ܮof solution. 20 ݉ܮ of this solution was transferred by pipette to a clean 250 mL volumetric flask andmade up to the mark. The molarity of the CH3NH2 in the final solution was determined to be 0.103 M.Determine the mass of CH3NH2 present in the original amount of impure compound used tomake this solution.and Employees CH STATE GE 90 ENDULERSE IS FOREVER "ON-Tame Name Jodi Rayal Molarity = wt. x1000 3. Calculate the massof Potassium hydrogen phthalate (KHP) to prepare a 250.0 mL solution of 0.1000 M KHP solution. Mol ut. x Voluse the 2500×1000 204.22250 mass Initial Buret Reading Final Buret Reading Vol NaOH Added Moles of NaOH Moles of HCI Volume of unknown HCI solution Concentration of HCI Average concentration of HCI of KHP = 5.11g 4. Complete the table below for the following neutralization reaction of an unknown concentration of hydrochloric acid with 0.100 M sodium hydroxide: Mu spate solution Trial 1 0 11.15 го data and calculate the concentration 15 Trial 2 11.15 22.15 Trial 3 22.15 33.25 abyh 067 LANDINUKASHU TROWTHCENTISSATE ARAD Ma That par މއކނި REMURNAR MISAMARALISERDRY Tile25 ppm of CaCO3 was found in the water sample obtained on the lake in the nearby town.Calculate the moles of CaCO3 having a molar mass of 100.09 g/mol in 10 liters of water samplesolution having a density of 997 kg/m3. (Ans.: 24.95 moles CaCO3)
- What volume of concentrated H2SO4 (18.OM) is required to prepare 550mL of 4.00M H2SO4 solution? Consider the reaction: BaCl2 + K2CrO4 → BaCrO4 + 2KCI a. How many grams of Barium chromate (253.33g/mol) can be obtained from 75.0mL of 0.150M BaCl2 solution? b. What volume of 0.500M K2CrO4 solution is required to react with the 75.0mL of 0.15M BaCl2 solution?What is the molarity of a solution in which 150g of CaO are dissolved in 1900mL of solution? (Use thefollowing given information: overline MW:Ca=40g/mol , O=16g/molA. 1.41 mol/LB. 0.0014 mol/LC. 0.0014 MD. 1.41 mRun 1 Run 2 Molarity of KMnO4 solution (M) from bottle 0.00101 0.00101 Initial reading of buret KMnO4 (mL) 0.62 11.35 Final reading of buret KMnO4 (mL) 11.33 21.70 Run 1 Run 2 Volume of KMnO4 solution (mL) Moles of MnO4- used for titration (mol) Moles of C2O42- in 100.0 mL of solution (mol) Molarity of C2O42- (M) Molarity of Cd2+ (M) Ksp of CdC2O4 Average Ksp of CdC2O4 Calculations: Moles of MnO4- used for titration of saturated solution CdC2O4 Moles of C2O42- in 100.0 mL of saturated solution of CdC2O4 Molarity of C2O42- in saturated solution of CdC2O4 Molarity of Cd2+ in saturated solution of CdC2O4 Solubility product, Ksp, of CdC2O4
- A volume of 125.0 mL of 0.565 M KOH (aq) is diluted with 425.0 mL of pure water. What is the final concentration (in molarity) of KOH? Report to three significant figures.a) convert 0.750 moles of CuCl2 to mass in grams. b) 25cm3 of sodium hydroxide solution of unknown concentration was filtrated with dilute sulphuric acide of concentration of 0.050 moldm-3 . 20cm3 was required to neturalie the sodiu hydroxide. calculate the concentration of the sodium hydroxide solution in moldm-3 nb. write the balanced equation use mole ratio to covert moles of sulphuric acid to moles of sodium hydroxide place moles in volume given cm3 then convert cm3 to dm3What volume of solution is needed to give 15.3 g of NaBr is the solution is 28.4% NaBr by volume and the density of the solution is 1.26 g/mL? Please answer very soon will give rating surely
- The aluminum in a 1.200-g sample of impure ammonium aluminum sulfate was precipitated with aqueous ammonia as the hydrous Al2O3.xH2O. The precipitate was filtered and ignited at to give anhydrous Al2O3, which weighed 0.2001 g. Express the result of this analysis in terms of %NH4Al(So4)2 %Al2O3 %AlData of NaOH Trial 1: mass=0.537g Volume =23.6ml Trial 2: mass=0.566g Volume = 26.8ml Trial 3: mass= 0.611g Volume = 23.4ml 1) calculate the molarity of NaOH for each trial and find the average molarity.10) How can you prepare 500 ml of 0.1M HCI, if the percentage is 35%, and density = 1.18g/ml, M.mass=36.5 g/mol