How many moles of Al are necessary to form 70.0 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.19PAE: 4.19 How many metric tons of carbon are required to react with 7.83 metric tons of Fe2O3 according...
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How many moles of Al are necessary to form 70.0 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

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