How many osmoles are there in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ?First we have to convert moles into osmolesMg3(PO4)23 Mg*22 РОД3+1 mol = 6 eq1 mol =osmoleseqmol(6.00 x 10-3 L)(--) =eq (-) =eqosmolmol MP)(---osmolmol MPа. 4b. 100.0С. 2d. 30.00е. 6f. 24g. 3h. 36i. 18.0j. 1k. 6.00 x 10-3I. 3.60 x 10-2m. 6.00 x 10-2n. 5О. 3.0 х 10-2р. 1.80 х 10-2q. 7.65 x 10-10r. 2.63S. 7.89t. 5.26u. 1012v. 109w. 106х. 103у. 95.21z. 10Mark for Review What's This?

Given the volume of 6.0 N Mg3(PO4)2 = 6.00 mL For Mg3(PO4)2, 1 mol = 6 eq

How many osmoles are there in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? First we have to convert moles into osmoles Mg3(PO4)2 3 Mg*2 2 Род3 + 1 mol = 6 eq 1 mol = osmoles eq mol (6.00 x 10-3 L)(- -) = eq(- %3D L eq osmol mol MP)(- -) = osmol mol MP а. 4 b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 o. 3.0 x 10-2 n. 5 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 u. 1012 v. 109 w. 106 х. 103 у. 95.21 z. 10

How many osmoles are there in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? First we have to convert moles into osmoles Mg3(PO4)2 3 Mg*2 2 Род3 + 1 mol = 6 eq 1 mol = osmoles eq mol (6.00 x 10-3 L)(- -) = eq(- %3D L eq osmol mol MP)(- -) = osmol mol MP а. 4 b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 o. 3.0 x 10-2 n. 5 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 u. 1012 v. 109 w. 106 х. 103 у. 95.21 z. 10

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.107E

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