How many times will the loop repeat? for (int x = 10; x< { } //Some codes.... 1; x++)
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Q: How many times will the loop repeat? for (int ctx = 0; ctx < 10; ctx ++) { } //Some codes....
A: The solution to the question is given in the below step
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- Because it is repeated so many times in the code, the statement or block of an endless loop is known as an infinite loop's block.Java - Write a method that uses a loop to figure out the factorial (n!). The method will take an integer n and return the value of n! (return answer, don’t print)What, in your opinion, is wrong with this nested for loop? for(int x = 0; x < 10; x++){ for(int x = 10; x > 0; x--){ System.out.println(x); } }
- JAVA program Write a while loop that prints all the even numbers from 1 to 100 (inclusive). and another while loop to print all the odd numbers from 1 to 100 (inclusive).How many time will the loop run? for( int i = 18 ; i < 65 ; i++ ) { }(Python) Which is the correct answer? This loop is best when you want the loop to run X amount of times. a. loopX b. while c. for d. do while
- Consider the following code segment. What is the value of i and sum2 after the for loop completes? int sum2 = 0, i = 0; for (int i = 0; i < 5; i++) sum2 = sum2 + i; cout << "Sum is: " << sum2 << " i is: " << i << endl;The following code is an example of what kind of loop? int count = 0; while (count < 10) { count++; }How many times is the body of the loop executed? The numbers on left are line numbers. 1 int i=1; 2 while(true) { 3 if(++i==5) { 4 break; 5 } 6 } Group of answer choices 3 Forever 6 4 5 Please explain answer.
- What is the result of the following code? int xNum T 0; int yNum = 0; do { xNum = xNum+yNum; yNum += 1; cout << "xNum: } while (xNum > 2); << xNum; O a.xNum: 2 is printed O b. no output, the loop is never executed O c. xNum: 0 is printed O d. endless loopwrite a loop that will display numbers in reverse order from 20 to 0Check to see what happens if the for loop’s condition is incorrectly written using the <= operator in printHourlyCounts: for(int hour = 0; hour <= hourCounts.length; hour++)