How much energy is required to heat 8.6kg of ice from -20℃ to steam at 120C ? The specific heat capacity of ice is 2.097 J/kg C The latent heat of fusion of ice is: Lf = 3.33 × 105J/kg The specific heat capacity of water is 4186J/kg C The latent heat of vaporization of water is: Lv = 22.6 × 105J/kg The specific heat capacity of steam is 1996 J/kg°C DO NOT include units. DO NOT write in scientific notation. Do not include any "spaces" in your answer. 1. The heat energy needed to raise the temperature of ice to 0 degrees Celcius (in Joules) = 2. The heat energy needed to convert ice to water at 0 degrees Celcius (in Joules) = 3. The heat energy needed to raise the temperature of water from 0 degrees to 100 degrees Celcius (in Joules)=

How much energy is required to heat 8.6kg of ice from -20℃ to steam at 120C ? The specific heat capacity of ice is 2.097 J/kg C The latent heat of fusion of ice is: Lf = 3.33 × 105J/kg The specific heat capacity of water is 4186J/kg C The latent heat of vaporization of water is: Lv = 22.6 × 105J/kg The specific heat capacity of steam is 1996 J/kg°C DO NOT include units. DO NOT write in scientific notation. Do not include any "spaces" in your answer. 1. The heat energy needed to raise the temperature of ice to 0 degrees Celcius (in Joules) = 2. The heat energy needed to convert ice to water at 0 degrees Celcius (in Joules) = 3. The heat energy needed to raise the temperature of water from 0 degrees to 100 degrees Celcius (in Joules)=

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter21: Heat And The First Law Of Thermodynamics

Section: Chapter Questions

Problem 71PQ

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Consider the latent heat of fusion and the latent heat of vaporization for H2O, 3.33 105 J/kg and 2.256 106 J/kg, respectively. How much heat is needed to a. melt 2.00 kg of ice and b. vaporize 2.00 kg of water? Assume the temperatures of the ice and steam are at the melting point and vaporization point, respectively. (a). UsingEq21.9, Q = mLF = (2.00 kg) (3.33l05 J/kg) = 6.66105 J (b).UsingEq21.10. Q = mLV = (2.00kg) (2.256106 J/kg) = 14.51106 J
What mass of steam initially at 130°C is needed to warm 200 g of water in a 100-g glass container from 20.0°C to 50.0°C?
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