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How much energy will be released by the reaction of 1 gram of 23>U by the following reaction: 235y + n- 144xe + 90sr + 2 'n (235U = 235.043922 g/mol, 'n 1.00866 g/mol 144xe = 143.9385 g/mol, 9USr = 89.907738 g/mol) %3D

How much energy will be released by the reaction of 1 gram of 23>U by the following reaction: 235y + n- 144xe + 90sr + 2 'n (235U = 235.043922 g/mol, 'n 1.00866 g/mol 144xe = 143.9385 g/mol, 9USr = 89.907738 g/mol) %3D

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter14: Nuclear Chemistry
Section: Chapter Questions
Problem 14.88PAE
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Moving to another question will save this response. Question 4 How much energy will be released by the reaction of 1 gram of 2PU by the following reaction: 235y + n → 144xe + 90sr + 2 n (235U = 235.043922 g/mol, 'n 1.00866 g/mol, 144Xe = 143.9385 g/mol, Sr= 89.907738 g/mol) A Moving to another question will save this response. AutoPlay W.
Transcribed Image Text:Moving to another question will save this response. Question 4 How much energy will be released by the reaction of 1 gram of 2PU by the following reaction: 235y + n → 144xe + 90sr + 2 n (235U = 235.043922 g/mol, 'n 1.00866 g/mol, 144Xe = 143.9385 g/mol, Sr= 89.907738 g/mol) A Moving to another question will save this response. AutoPlay W.
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