How to caculate the frequency for genotype and phenotypeStudent #Genotype (4/4,⅘,5/5)Chronotype numberPhenotype (Morning 59-86, Intermediate42-58,Evening 16-41)Student 1 4,551IntermediateStudent 2 5,533EveningStudent 34,540EveningStudent 4 5,552IntermediateStudent 5 5,551IntermediateStudent 6 4,439EveningStudent 7 4,446IntermediateStudent 8 4,448IntermediateStudent 9 4,559MorningStudent 105,531Evening Student 114,539Evening Genotype# of studentsFrequencyPhenotype# of studentsFrequency4/43?Morning 59-861?4/54 Intermediate42-585 5/54 Evening 16-415

Name: How to caculate the frequency for genotype and phenotypeStudent #Genot
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: How to caculate the frequency for genotype and phenotypeStudent #Genotype (4/4,⅘,5/5)Chronotype numberPhenotype (Morning 59-86, Intermediate42-58,Evening 16-41)Student 1 4,551IntermediateStudent 2 5,533EveningStudent 34,540EveningStudent 4 5,552Inte

Genotype frequency is the number of individuals with a certain genotype (homozygous dominant,…

Answered: How to caculate the frequency for…

Science

Biology

How to caculate the frequency for genotype and phenotype

An Illustrated Guide To Vet Med Term

4th Edition

ISBN:9781305465763

Author:ROMICH

Publisher:ROMICH

Chapter5: What Is In A Name

Section: Chapter Questions

Problem 1CP

See similar textbooks

Similar questions

Have the student use the infomration obtain regarding the USA population to determine the “Expected” frequency and counts as well as having them to analyze the data and provide phenotype, genotype and allele frequencies plus the perform chi-square analyses. Have the student to complete every single empty square. For frequencies, (O-E)2/E and x^2 round to two decimal places. Use whole numbers for counts… people are counted in whole numbers!
I need help in table 2 & 3 please Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 433.875 129.875 16789.68 38.69 Disease, Female 267 433.875 166.875 26855.01 61.89 WT, Male 285 144.625 140.375 19705.14 136.25 WT, Female 301 144.625 156.375 24453.15 156.37 Total 1157 1157 393.20 DF 3 p-value 7.84 Expected progencies as per SLR MOI’s = 1:1 for both male and female Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 289.25 14.75 217.56 0.75 Disease, Female 267 289.25 22.25 495.06 1.85 WT, Male 285 289.25 4.25 18.06 0.06 WT, Female 301 289.25 11.75 138.06 0.46 Total 1157 1157 3.12 DF 3 p-value 7.84 Progenies are following SR MOI’s that parents have genotypes and progenies in ratio 1:1 In Table 2,…
A population of frogs consists of 1000 individuals of which 400 are red. Red is recessive to Green. What is the frequency of the dominant allele and the recessive allele in this population? What is the frequency of individuals with homozygous dominant phenotypes? Please answer and show all work, thank you!! :)
If only the first five loci listed in Table 1 of the assigned paper (Forensics, DNA Fingerprinting, and CODIS) were analyzed, what would be the statistical probability of finding that particular genotype among people other than Suspect B? SHOW YOUR WORK! Hint: Multiply together the frequencies of the individual STR genotypes to obtain the overall profile frequency.
Write the survivor rate for AA and Aa genotypes (write the answer in decimal numbers, not in fractions) Survivor rate of AA= Survivor rate of Aa= Write the absolute fitness for AA and Aa genotypes (write the answer including two decimal figures) Absolute fitness (W) of AA= Absolute fitness (W) of Aa= Write the relative fitness for AA and Aa genotypes (write the answer in decimal numbers, include two decimal figures) Relative fitness (w) of AA= Relative fitness (w) of Aa= asap please.
How many individuals need to be genotyped in order to get an acceptable estimate of the rarity of alleles used for DNA profiling purposes? About 200 About 2,000 About 20,000 About 2,000,000 About 20,000,000
Written Response 1a) Identify the genotypes of individuals ii-1, ii-4, iii-4, and IV-1. b) If individual III-9 and individual III-10 have another child, what is the probability that this child will have normal colour vision? Sketch a punnett square to support your answer (be creative -- you can type this up on the computer) c) Determine the frequency of the achromatopsia allele in the population illustrated in the pedigree. Round your answer to three decimal places. Show your work.
Phenotype and Genotype ratio help!
There are 1024 individuals with the genotype GG, 512 individuals with a genotype Gg, and 64 individuals with the genotype gg. Useless information to find the dominant allele frequency the recessive allele frequency the homozygous dominant frequency the heterozygous frequency and the homozygous recessive frequency
Note there are no cells on this panel that have a double dose (homozygous) of the K antigen. Which of the following statements is true regarding the K+k- phenotype? Question 6 options: A) The phenotype is rare due to the high prevalence of the k antigen in the population. B) The phenotype is uncommon but does occur in about 10% of the population. C) The phenotype occurs in about 50% of the population. D) Although the phenotype is not represented on this antibody panel, it is fairly common in the population.
Using the two equations, p + q = 1 and p2 + 2pq + q2 = 1, answer the following questions. Maple Syrup Urine Disease (MSUD) is an autosomal recessive condition that causes intellectual and physical disabilities, difficulty feeding, and a sweet maple syrup odor to the urine. In Costa Rica, the incidence of MSUD is calculated as approximately 1 in 8,000 newborns. Calculate the allele frequencies for the normal and disease alleles.
An individual ______ determines its observable _________. 1-gene location, allele 2- phenotype, genotype 3- homozygote, heterozygote 4- heterozygote, homozygote 5 - genotype, phenotype

SEE MORE QUESTIONS

Recommended textbooks for you

An Illustrated Guide To Vet Med Term

Biology

ISBN:

9781305465763

Author:

ROMICH

Publisher:

Cengage

An Illustrated Guide To Vet Med Term

Biology

ISBN:

9781305465763

Author:

ROMICH

Publisher:

Cengage

SEE MORE TEXTBOOKS

GET THE APP

About FAQ Academic Integrity Sitemap Document Sitemap

Contact Bartleby Contact Research (Essays)High School Textbooks Literature Guides Concept Explainers by Subject Essay Help Mobile App

GET THE APP

Privacy

Your CA Privacy Rights

Your NV Privacy Rights

About Ads

Manage My Data

bartleby, a Learneo, Inc. business

Student #	Genotype (4/4,⅘,5/5)	Chronotype number	Phenotype (Morning 59-86, Intermediate 42-58,Evening 16-41)
Student 1	4,5	51	Intermediate
Student 2	5,5	33	Evening
Student 3	4,5	40	Evening
Student 4	5,5	52	Intermediate
Student 5	5,5	51	Intermediate
Student 6	4,4	39	Evening
Student 7	4,4	46	Intermediate
Student 8	4,4	48	Intermediate
Student 9	4,5	59	Morning
Student 10	5,5	31	Evening
Student 11	4,5	39	Evening

Genotype	# of students	Frequency	Phenotype	# of students	Frequency
4/4	3	?	Morning 59-86	1	?
4/5	4		Intermediate 42-58	5
5/5	4		Evening 16-41	5