How would you prepare 100ml of 0.5m solution using stock solution? please explain your answer IntroductionA 1.0 M solution contains 1 mole of that substance in 1 liter of solution, and a 1.0 N solution contains1 equivalent weight of substance per liter of solution.Since the molecular weights of Na = 22.99 and Cl = 35.45For NaCl, one mole = 1 equivalent weight = 58.44 g%3DTherefore 1M solution = 58.44 gm of NaCl dissolved in 1 liter of distilled water or5.844 gm of NaCl dissolved in 100 ml of distilled water Solution A1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the stock solution to anothervolumetric flask2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.Since this a ten times dilution the, Molarity of this solution isSolution B1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the Solution A to anothervolumetric flask2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.Since this a ten times dilution the, Molarity of this solution is =M

Solution : The molarity of the solution is defined as the number of moles of solute per liter…

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How would you prepare 100ml of 0.5m solution using stock solution? please explain your answer

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.27QAP

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

100%

How would you prepare 100ml of 0.5m solution using stock solution?

please explain your answer

Introduction
A 1.0 M solution contains 1 mole of that substance in 1 liter of solution, and a 1.0 N solution contains
1 equivalent weight of substance per liter of solution.
Since the molecular weights of Na = 22.99 and Cl = 35.45
For NaCl, one mole = 1 equivalent weight = 58.44 g
%3D
Therefore 1M solution = 58.44 gm of NaCl dissolved in 1 liter of distilled water or
5.844 gm of NaCl dissolved in 100 ml of distilled water

Solution A
1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the stock solution to another
volumetric flask
2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.
Since this a ten times dilution the, Molarity of this solution is
Solution B
1. Using a pipette pump, and a 10ml pipette, transfer 10ml of the Solution A to another
volumetric flask
2. Make up to the 100ml mark with distilled water, stopper the flask and shake well.
Since this a ten times dilution the, Molarity of this solution is =
M

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