Hydrogen and iodine react to form hydrogen iodide, like this: H,(9)+I,(g) → 2 HI(g) Use this chemical equation to answer the questions in the table below. Suppose 115. mmol of H, and O None. 115. mmol of I, are added to an O Some, but less than 115. mmol. empty flask. How much H, will be in O 115. mmol. the flask at equilibrium? O More than 115. mmol. O None. Suppose 55.0 mmol of HI are added O Some, but less than 55.0 mmol. to an empty flask. How much HI will be in the flask at equilibrium? O 55.0 mmol. More than 55.0 mmol.

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Hydrogen and iodine react to form hydrogen iodide, like this:
H2(g)+I,(g) → 2 HI(g)
Use this chemical equation to answer the questions in the table below.
Suppose 115. mmol of H, and
O None.
115. mmol of I, are added to an
O Some, but less than 115. mmol.
empty flask. How much H, will be in
O 115. mmol.
the flask at equilibrium?
O More than 115. mmol.
O None.
Suppose 55.0 mmol of HI are added
O Some, but less than 55.0 mmol.
to an empty flask. How much HI will
be in the flask at equilibrium?
O 55.0 mmol.
O More than 55.0 mmol.
Continue
O2021 McGraw Hi
MacBook Air
Transcribed Image Text:Hydrogen and iodine react to form hydrogen iodide, like this: H2(g)+I,(g) → 2 HI(g) Use this chemical equation to answer the questions in the table below. Suppose 115. mmol of H, and O None. 115. mmol of I, are added to an O Some, but less than 115. mmol. empty flask. How much H, will be in O 115. mmol. the flask at equilibrium? O More than 115. mmol. O None. Suppose 55.0 mmol of HI are added O Some, but less than 55.0 mmol. to an empty flask. How much HI will be in the flask at equilibrium? O 55.0 mmol. O More than 55.0 mmol. Continue O2021 McGraw Hi MacBook Air
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