I can't seem to find the shear stress at point b. Here's my work for reference. 54Homework 121. F= P. CL2.L3) = 13.5 (9.3f+- 14.4ft) = -1807,92 lbNormal Sheor stress Cequal to all points)▷do-di - €ADKKDKKeTorsional shear stress Cequal to all Points).▷T = F • ²2/2/2/2 = 1807.92-16.13,017.024 1boftJ = 3/2 (9.5₁4-8.88 in") = 189.2 in 1DC torsional = 13,017.024 16.12:031189.2 in CIO.a. sinDNormalDTnormanCorsionalShedB|CB| =AJ23181807.9216(9.52-8,882)ос - МС→ do-di= 2€ di = do-26=9.5-2(0.31) = 8.88 inDTc = √√√ 202² + 3921.882T1.4= 202 psisi14.4FF1354eT20PED202² + 3921.882 = 3927.1 psi202-3921.88 = 3719.88 psi2:1807.92 (32 +93). 122. (9.5द4 (9.54-8.88५)220273921.88 psp 301273TERUS-39926.9 psiA24 An advertising sign located along a city street is cantilevered from a pole as shown below. The pressure due tothe wind impinging on the sign is uniformly distributed over its area and equal to p = 13.5 lb/ft² in the x-direction. The pole is fabricated from a tube with an outside diameter of do= 9.5 in. and a wall thickness oft = 0.31 in. Determine the stresses at points Cand Blocated at the base of the pole.Given:.• L₁=32 ftL₂=9.3 ft11L3go=pr|TC=14.4 ft3.927OB-0L2L₁XZL3 →yDAB✓ 100%ksi @ 100%- 100%XOX

Given-Information: L1=32ftL2=9.3ftL3=14.4ftp=13.5lb/ft2do=9.5int=0.31in To-Determine: Stress at B,…

Answered: I can't seem to find the shear stress…

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I can't seem to find the shear stress at point b. Here's my work for reference.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.3.1P: A fire extinguisher tank is designed for an internal pressure of 825 psi. The tank has an outer...

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

I can't seem to find the shear stress at point b. Here's my work for reference.

54
Homework 12
1. F= P. CL2.L3) = 13.5 (9.3f+- 14.4ft) = -1807,92 lb
Normal Sheor stress Cequal to all points)
▷do-di - €
A
D
K
K
D
K
K
e
Torsional shear stress Cequal to all Points).
▷T = F • ²2/2/2/2 = 1807.92-16.
13,017.024 1boft
J = 3/2 (9.5₁4-8.88 in") = 189.2 in 1
DC torsional = 13,017.024 16.12:0
31189.2 in CIO.
a. sin
D
Normal
D
Tnorman
Corsional
Shed
B
|CB| =
AJ
2318
1807.9216
(9.52-8,882)
ос - МС
→ do-di= 2€ di = do-26=9.5-2(0.31) = 8.88 in
D
Tc = √√√ 202² + 3921.882
T
1.4
= 202 psisi
14.4FF
1354
e
T20
PED
202² + 3921.882 = 3927.1 psi
202-3921.88 = 3719.88 psi
2:1807.92 (32 +93). 122. (9.5
द4 (9.54-8.88५)
2
20273921.88 psp 301
27
3
TERUS
-39926.9 psi
A
24

An advertising sign located along a city street is cantilevered from a pole as shown below. The pressure due to
the wind impinging on the sign is uniformly distributed over its area and equal to p = 13.5 lb/ft² in the x-
direction. The pole is fabricated from a tube with an outside diameter of do= 9.5 in. and a wall thickness of
t = 0.31 in. Determine the stresses at points Cand Blocated at the base of the pole.
Given:
.
• L₁=32 ft
L₂=9.3 ft
11
L3
go=
pr
|TC=
14.4 ft
3.927
OB-0
L2
L₁
X
Z
L3 →
y
D
A
B
✓ 100%
ksi @ 100%
- 100%
XOX

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