I could really use help with void-user defined, value-returning functions. here's my Instructions for my C++ program: The function printGrade in Example 6-13 is written as a void function to compute and output the course grade. The course score is passed as a parameter to the function printGrade. Rewrite the function printGrade as a value-returning function so that it computes and returns the course grade. (The course grade must be output in the function main.) Also, change the name of the function to calculateGrade.The function printGrade has been posted below for your convenience. void printGrade(int cScore){cout << "The course grade is: "; if (cScore >= 90) {cout << "A." << endl; } else if (cScore >= 80) {cout << "B." << endl;} else if(cScore >= 70) {cout << "C." << endl;} else if (cScore >= 60) {cout << "D." << endl; } else {cout << "F." << endl; } I don't understand how to program a void function. It doesn't make sense to me. Can anyone help me to finish this program? I would appreciate it.
I could really use help with void-user defined, value-returning functions.
here's my Instructions for my C++
The function printGrade in Example 6-13 is written as a void function to compute and output the course grade. The course score is passed as a parameter to the function printGrade. Rewrite the function printGrade as a value-returning function so that it computes and returns the course grade. (The course grade must be output in the function main.) Also, change the name of the function to calculateGrade.
The function printGrade has been posted below for your convenience.
void printGrade(int cScore)
{
cout << "The course grade is: ";
if (cScore >= 90) {
cout << "A." << endl;
} else if (cScore >= 80) {
cout << "B." << endl;
} else if(cScore >= 70) {
cout << "C." << endl;
} else if (cScore >= 60) {
cout << "D." << endl;
} else {
cout << "F." << endl;
}
I don't understand how to program a void function. It doesn't make sense to me. Can anyone help me to finish this program? I would appreciate it.
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