I have no problem finding for the recursion version but for iteration I am unable to do so as the results are different. def gibonacci_R(n): if n <= 1 : return 0 elif n == 2 : return 1 else: return gibonacci_R(n-1) + gibonacci_R(n-3) def gibonacci_I(n): if n <= 1 : return 0 elif 2 <= n < 4: return 1 x = 1 y = 0 for i in range (4,n+1,1): current = x y = x  x = current return current   I should be getting: gibonacci_I(4) == 1 gibonacci_I(5) == 2 gibonacci_I(6) == 3 gibonacci_I(7) == 4 gibonacci_I(8) == 6 gibonacci_I(9) == 9 gibonacci_I(10) == 13 gibonacci_I(11) == 19 gibonacci_I(12) == 28 gibonacci_I(13) == 41 gibonacci_I(14) == 60 gibonacci_I(15) == 88

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I have no problem finding for the recursion version but for iteration I am unable to do so as the results are different.

def gibonacci_R(n):
if n <= 1 :
return 0
elif n == 2 :
return 1
else:
return gibonacci_R(n-1) + gibonacci_R(n-3)

def gibonacci_I(n):
if n <= 1 :
return 0
elif 2 <= n < 4:
return 1
x = 1
y = 0
for i in range (4,n+1,1):
current = x
y = x 
x = current
return current

 

I should be getting:

gibonacci_I(4) == 1

gibonacci_I(5) == 2

gibonacci_I(6) == 3

gibonacci_I(7) == 4

gibonacci_I(8) == 6

gibonacci_I(9) == 9

gibonacci_I(10) == 13

gibonacci_I(11) == 19

gibonacci_I(12) == 28

gibonacci_I(13) == 41

gibonacci_I(14) == 60

gibonacci_I(15) == 88

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