I have the 4th edition of Tro Nivaldo's Chemistry: a Molecular Approach book and on page 731 the Ka value of HF is given as 6.8 x 10^-4, but in the solutions guide on bartleby for the end of chapter question chapter 17 question 33b, the HF values is 3.5 x 10^-4. Furthermore, google gives the Ka value of HF as 7.2 x 10^-4. Can you explain why I'm seeing all of these different values?

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter3: Molecules, Moles, And Chemical Equations
Section: Chapter Questions
Problem 3.102PAE: 3.102 Classify the following compounds as acids or bases, weak or strong. (a) perchloric acid, (b)...
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I have the 4th edition of Tro Nivaldo's Chemistry: a Molecular Approach book and on page 731 the Ka value of HF is given as 6.8 x 10^-4, but in the solutions guide on bartleby for the end of chapter question chapter 17 question 33b, the HF values is 3.5 x 10^-4. Furthermore, google gives the Ka value of HF as 7.2 x 10^-4. Can you explain why I'm seeing all of these different values?

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