I need help understanding each line of code. Can you please explain each line of code so I can fully understand what is going on step by step? I have experience in c++ so maybe you can also point out some differences between this code and c++ code. Thank you! #include int main(void) { char *stringPtr = "Hello world.\n"; while (*stringPtr != '\0') { printf("%p: ", stringPtr); printf("0x%02x\n", *stringPtr); stringPtr++; } printf("%p: ", stringPtr); printf("0x%02x\n", *stringPtr); return 0; }
I need help understanding each line of code. Can you please explain each line of code so I can fully understand what is going on step by step? I have experience in c++ so maybe you can also point out some differences between this code and c++ code. Thank you! #include int main(void) { char *stringPtr = "Hello world.\n"; while (*stringPtr != '\0') { printf("%p: ", stringPtr); printf("0x%02x\n", *stringPtr); stringPtr++; } printf("%p: ", stringPtr); printf("0x%02x\n", *stringPtr); return 0; }
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter14: Exception Handling
Section: Chapter Questions
Problem 14SA
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I need help understanding each line of code. Can you please explain each line of code so I can fully understand what is going on step by step? I have experience in c++ so maybe you can also point out some differences between this code and c++ code. Thank you!
#include <stdio.h>
int main(void)
{
char *stringPtr = "Hello world.\n";
while (*stringPtr != '\0')
{
printf("%p: ", stringPtr);
printf("0x%02x\n", *stringPtr);
stringPtr++;
}
printf("%p: ", stringPtr);
printf("0x%02x\n", *stringPtr);
return 0; }
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