i need the answer quickly HWQ.1The chemical analysis of formation water as follow;concentration (ppm)lonNa14,000CI12,000Mg10,000Ca8,000SO411,000Room temperature=D75°FCalculate formation water resistivity at 75, 125 and 150 °F.Q.2Formation water contains 10,000 ppm of NaCL, 15,000 ppm ofMgSO4 and 8,000 ppm of CaCl2 . Calculate the resistivity atformation temperature 200 °F.HWQ.3Calculate formation water resistivity at 150 °F if the concentrationof Nacl 50,000, 100,00 1nd 150,000 using graph and equations.Q.4If the formation resistivity in the above cases (Q.3) is 2.4 Q-m at225 °F and the cementation factor is 2. Calculate the porosityfor each case.

HW Q.1 The chemical analysis of formation water as follow; concentration (ppm) 14,000 12,000 lon Na CI Mg 10,000 8,000 Ca SO4 11,000 Room temperature=D75°F Calculate formation water resistivity at 75, 125 and 150 °F.

HW Q.1 The chemical analysis of formation water as follow; concentration (ppm) 14,000 12,000 lon Na CI Mg 10,000 8,000 Ca SO4 11,000 Room temperature=D75°F Calculate formation water resistivity at 75, 125 and 150 °F.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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