labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal.) 1) H₂N с b The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is 2) C The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) bis The number of lines exhibited by hydrogen(s) c is

EBK A SMALL SCALE APPROACH TO ORGANIC L
4th Edition
ISBN:9781305446021
Author:Lampman
Publisher:Lampman
Chapter95: Nuclear Magnetic Resonance Spectroscopy (proton Nmr)
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Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal. Predict the number of lines exhibited by hydrogens at the
labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal.)
1)
پیش رود
H₂N
The number of lines exhibited by hydrogen(s) a is
The number of lines exhibited by hydrogen(s) b is
The number of lines exhibited by hydrogen(s) c is
2)
b
с
a
The number of lines exhibited by hydrogen(s) a is
The number of lines exhibited by hydrogen(s) b is
The number of lines exhibited by hydrogen(s) c is
Transcribed Image Text:Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal. Predict the number of lines exhibited by hydrogens at the labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal.) 1) پیش رود H₂N The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is 2) b с a The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is
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I saw somewhere else that the answer for part b), The number of lines exhibited by hydrogen(s) b is, 6 not 12.

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