I+ Sin2X t Cos 2x COSX

Q: secx cos )

A:

Q: Sinx=1/2 Cos2x=

A:

Q: 12 sinx Cos X=

A:

Q: 4. x = 3 + 4 sine, y = 3cos0 - 4

A: Given: x=3+4sinθ, y=3cosθ-4 dxdθ=ddθ3+4sinθ = 4cosθ dydθ=ddθ3cosθ-4 = -3sinθ

Q: 311 = Sinx %3D COS

A:

Q: 2. Cos sin

A:

Q: sinx + cosx 1 + 2 sinxcosx %3D sinx - cosx 1 - 2cos?x

A: Question 52   Consider the equation:

Q: cos 4z - cos 2z =

A: cosx−cosy​=−2sinx+y2sinx−y​2​

Q: JOTICE sinx= IC X = 2. -Cos X OTICE

A: sin(x)= cos(x) when x= π/4

Q: Sinx -cos2y=l COS

A: If f(x) and g(x) are the functions of 'x' . Now, differentiate y= f(g(x)) with respect to 'x' , then…

Q: sin' (2t) cos? (2t) dt

A: Use the substitution and replace the terms by new variable and solve easily.

Q: CoS 2X sin x,co

A:

Q: Sin (Cos8X) Find dy

A: Given,           y=sincos8x

Q: 3- y 4 cos 3t - 2 sin 3t

A:

Q: Sinx=1/3 Cosx=?

A:

Q: cos2x Evaluate dx sin²2x- 16 12

A: This definite integral is based on the substitution method.

Q: sin 2x cos 2X I+ 3 cos4X

A:

Q: Sin(2x)Cos(nx) da

A: Law :  2sinAcosB = sin(A+B) + sin(A-B)

Q: 음 (sin-" (2))\_-+ = (교2)) | dx 2(:) A 1+ 2() B (C 2 (4) cos-1 (16) D -2 (금) cot () csc(6) CSC

A:

Q: / sin 3r cos 3xdx

A:

Q: sin 2x (1 - 2 cos 2x)? dx 6.

A:

Q: [*(sin³r)√1 + cos ar dr x

A: We know that integration power rule is given as  Integration of xn is xn+1/n+1.   Here i attached…

Q: cos (x) 2 %3D X = Submit

A:

Q: y = 3 sin' 2 x у

A:

Q: I = sin³x cos³x dx

A: Given the integration : ∫sin3 xcos3 xdx

Q: sin4x substitution - cos 4x(2 – 3sec4x)

A:

Q: 1. sin

A:

Q: i. |sin² xcos² xdx

A: We have to find

Q: sin(20) = cos(0) %3D

A:

Q: Sinx=2/3 Cosx=? Tanx=?

A: Question is solved.

Q: cos (0) tan (0)+3tan(0)=0

A: cosθtanθ+3tanθ=0

Q: Cos 2x %3D 1-sin 2x

A:

Q: Cos3 cos³x S dx 1+ sinx

A:

Q: Sc sinx te Cos

A: Given: The integral ∫cos22x sinx dx To evaluate: The given integral.

Q: Solve y'-y cosx = cos x

A: We now solve the differential equation, y' -ycosx=cosx . This is a first order homogeneous equation.

Q: [sin³ (2) cos(4) dx

A: Follow the procedure given below.

Q: cos° (3x) sin (3x) dr

A: Given data:     The given integral expression is: .   Assume cos(3x)=t, and differentiate it both…

Q: 1. cos t (1 + tan²t) sin ß sec ß + cos ß csc ß 2.

A: Given : 1. cost1+tan2t2. sinβsecβ+cosβcscβ

Q: 1– sin 2x

A: We have given (sin x – cos x)2 = 1 – sin 2x

Q: sin 3x cos“ 3xdx

A:

Q: sin' cos )d» 4х. 4x, 8

A:

Q: sin? cos dx 4x. 4x, 8 5 5

A:

Q: sin 2e - 2p cor ) de = 2 dp. Cord

A:

Q: + Sin (2x) de

A:

Q: COS X+ 3sin 2X

A: It is given that y''+y=cosx+3sin2x. We have to find the general solution of the given…

Q: cos –1 (-V)] 2 sec OS

A: Simplification

Q: sinx find: - dx 3 cos2x +1

A: find ∫sinxcos2x+13 dx first lets simplify it and then find the integral

Q: cos2x /(sin x+cosx)

A: cos2x(sinx+cosx)

Q: cos (x2 + 3x +5 ) COS

A: Solved below

Q: .csc(2x + :-2, where x € ( =) 4 - sin? () + cos²x = 1,where x € [0, 21) %3|

A: This question is related to trigonometric functions. Solve in step2.

Fundamentals of Trigonometric Identities

Trigonometric Identities are the equalities that involve trigonometry functions and hold for all the values of variables given in the equation.