I want to know the process of interpolation of H2' . How can I do this with superheated steam table? can you show me the exact process?  I don't know how to interpolation it from the steam table ( I don't know what values to use)   Here's a steam table. Could you show me the process of selecting value to interpolating? https://view.officeapps.live.com/op/view.aspx?src=https%3A%2F%2Flearncheme.com%2Fwp-content%2Fuploads%2F2022%2F11%2FSteam_Tables_1.21.xlsx&wdOrigin=BROWSELINK

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I want to know the process of interpolation of H2' .

How can I do this with superheated steam table? can you show me the exact process? 

I don't know how to interpolation it from the steam table ( I don't know what values to use)

 

Here's a steam table. Could you show me the process of selecting value to interpolating?

https://view.officeapps.live.com/op/view.aspx?src=https%3A%2F%2Flearncheme.com%2Fwp-content%2Fuploads%2F2022%2F11%2FSteam_Tables_1.21.xlsx&wdOrigin=BROWSELINK

Example 7.8
Saturated-vapor steam at 100 kPa (tsat = 99.63°C) is compressed adiabatically to
300 kPa. If the compressor efficiency is 0.75, what is the work required and what are
the properties of the discharge stream?
7.3. Compression Processes
Solution 7.8
For saturated steam at 100 kPa,
S₁ =7.3598 kJ-kg-¹.K-1
For isentropic compression to 300 kPa, S₂ = S₁ = 7.3598 kJ-kg-¹.K-¹. Interpo-
lation in the tables for superheated steam at 300 kPa shows that steam with this
entropy has the enthalpy: H₂ = 2888.8 kJ-kg-¹.
Thus,
(AH)s=2888.8 - 2675.4 = 213.4 kJ-kg-1
H₁ = 2675.4 kJ-kg-¹
-1
(ΔΗ), 213.4
n
0.75
H₂ = H₁ + AH = 2675.4+284.5 = 2959.9 kJ-kg-1
(ΔΗ) = ·
By Eq. (7.17),
and
For superheated steam with this enthalpy, interpolation yields:
T2 = 246.1°C S₂ = 7.5019 kJ-kg-¹.K-1
= 284.5 kJ-kg-¹
Moreover, by Eq. (7.14), the work required is:
W, = AH = 284.5 kJ-kg-¹
285
Transcribed Image Text:Example 7.8 Saturated-vapor steam at 100 kPa (tsat = 99.63°C) is compressed adiabatically to 300 kPa. If the compressor efficiency is 0.75, what is the work required and what are the properties of the discharge stream? 7.3. Compression Processes Solution 7.8 For saturated steam at 100 kPa, S₁ =7.3598 kJ-kg-¹.K-1 For isentropic compression to 300 kPa, S₂ = S₁ = 7.3598 kJ-kg-¹.K-¹. Interpo- lation in the tables for superheated steam at 300 kPa shows that steam with this entropy has the enthalpy: H₂ = 2888.8 kJ-kg-¹. Thus, (AH)s=2888.8 - 2675.4 = 213.4 kJ-kg-1 H₁ = 2675.4 kJ-kg-¹ -1 (ΔΗ), 213.4 n 0.75 H₂ = H₁ + AH = 2675.4+284.5 = 2959.9 kJ-kg-1 (ΔΗ) = · By Eq. (7.17), and For superheated steam with this enthalpy, interpolation yields: T2 = 246.1°C S₂ = 7.5019 kJ-kg-¹.K-1 = 284.5 kJ-kg-¹ Moreover, by Eq. (7.14), the work required is: W, = AH = 284.5 kJ-kg-¹ 285
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