Total Load = 40 + 150 + 100 + 60 + 40 = 390KNRD = 217.62RB = 172.38 I50 KN30KN30 KNJORNAC19 KB4m24Find the reactions at A & Dequatims(2) Wn te the shear & momeaah the beamfum AB; B-C, C D X 0Ecomentinh.(3) By graplical me thod draw theshear & momant diagran4) By the shom & moment egruatinsdraw the shon f moment dingraunthe beam.the han

Answered: Image /qna-images/answer/8bf90a9c-c9e0-48bd-be9e-358cbae30d75.jpg

Answered: I50 KN 30KN 3o KN JOKN C19 F B. IM 4m.…

I50 KN 30KN 3o KN JOKN C19 F B. IM 4m. 24 O Find the reactions at A &Dequatins (2) Wnite the shear & momen fom AB; B-C, C D X 0E tiah the bea

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

100%

Total Load = 40 + 150 + 100 + 60 + 40 = 390KN

RD = 217.62

RB = 172.38

I50 KN
30KN
30 KN
JORN
A
C19 K
B
4m
24
Find the reactions at A & Dequatims
(2) Wn te the shear & momeaah the beam
fum AB; B-C, C D X 0E
comentinh.
(3) By graplical me thod draw the
shear & momant diagran
4) By the shom & moment egruatins
draw the shon f moment dingraun
the beam.
the han

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