if 80g of ethanol (CH5OH) are burnt completely, how many molecules of water would be produced ? CH5OH(I)+2O2(g)=CO2(g)+3H2O(I)

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.2: Reactions In Which One Reactant Is Present In Limited Supply
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if 80g of ethanol (CH5OH) are burnt completely, how many molecules of water would be produced ? CH5OH(I)+2O2(g)=CO2(g)+3H2O(I)
steps to solve the problem.
If 80g of ethanol (CH,OH) are burnt completely, how many molecules of water would be produced?
CH,OH(I) + 20,(g)→ Co.(g) + 3H,0(I)
Transcribed Image Text:steps to solve the problem. If 80g of ethanol (CH,OH) are burnt completely, how many molecules of water would be produced? CH,OH(I) + 20,(g)→ Co.(g) + 3H,0(I)
Expert Solution
Step 1

Given combustion reaction of ethanol is as follows(corrected equation) :

C2H5OH (I) + 3O2 (g) -----> 2CO2 (g) +   3H2O (I)

given amount of ethanol available for combustion = 80 g

Molecular mass of ethanol = 46.07 g/mol

Moles of ethanol in given mass = 80 g/46.07 g/mol

   = 1.74 moles 

 

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