If A and B are similar, then there exists a matrix P such that B = PAP. Use this fact to fi -2 2 -3 2 P 3D -2 1 A = 1-2 -6 5 2-3
If A and B are similar, then there exists a matrix P such that B = PAP. Use this fact to fi -2 2 -3 2 P 3D -2 1 A = 1-2 -6 5 2-3
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.3: Symmetric Matrices And Orthogonal Diagonalization
Problem 60E: Find ATA and AAT for the matrix below. What do you observe? A=[132461]
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