If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t) = 48 + 112t – 16t2. What is the maximum height the ball reaches? Answer: 244 What is the velocity of the ball when it hits the ground (height 0)? Answer:

If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t) = 48 + 112t – 16t2. What is the maximum height the ball reaches? Answer: 244 What is the velocity of the ball when it hits the ground (height 0)? Answer:

Name: If a ball is thrown vertically upward from the roof of 48 foot buildi
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Description: If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 112ft/sec, its height after t seconds is s(t) = 48 + 112t – 16t2. What is the maximum height the ballreaches?Answer: 244What is the velocity of the ball when

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter3: Accelerated Motion

Section: Chapter Questions

Problem 4STP

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