If a line is parallel to the vector 8i + 5j + 3k and passes through the point P = (6,2,4), then the parametric equation of the line is : O a. X=-6-8A, Y=- 2- 5), Z= -4-3A O b. X=6-8A, Y= 2- 5A, Z= 4-3A O c. X=6+ 8A, Y= 2+ 5^, Z= 4+3A d. X=-6+ 8A, Y= -2+ 5^, Z= -4+3\

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter1: Vectors
Section1.3: Lines And Planes
Problem 34EQ
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If a line is parallel to the vector 8i + 5j+ 3k and passes through the point P = (6, 2, 4), then the parametric equation of the line is :
a. X=-6-8A, Y=- 2- 51, Z= -4-3A
b. X=6-8A, Y= 2- 51, Z= 4-3A
c. X=6+ 8\, Y= 2+ 5^, Z= 4+3A
d. X=-6+ 8A, Y= -2+ 51, Z= -4+3A
Transcribed Image Text:If a line is parallel to the vector 8i + 5j+ 3k and passes through the point P = (6, 2, 4), then the parametric equation of the line is : a. X=-6-8A, Y=- 2- 51, Z= -4-3A b. X=6-8A, Y= 2- 51, Z= 4-3A c. X=6+ 8\, Y= 2+ 5^, Z= 4+3A d. X=-6+ 8A, Y= -2+ 51, Z= -4+3A
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