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Please do not give solution in image formate thanku
If a planet has an average distance from the Sun of 1.9 AU, what is its orbital period?
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- Please do not give solution in image format thanku considering that the planet takes approximately 76.3 earth yearsfor it to complete one revolution around the sun, approximately what would be the length of the planet's day?Which planet should I start with? USE IMAGE AS REFERNCENOTE: Answer of 15.2 and 15.151 are wrong answers given to me here on Barteby. Could I please have the correct answer?
- Imagine that a new dwarf planet is found in the solar system with a semi-major axis of 52.2 [AU]. What is the orbital period of the new world in Earth years? Use kelpers third lawSuppose you discovered a new celestial body going around the sun. If it requires 512 years to complete one orbit around the sun, what is its average distance from the sun? ( give answer in AU)Where T = orbital period in Earth years and R = distance of the planet from the sun in A.U.’s. From this equation how would you describe the relationship between T2 and R3?
- what are the factors that lead to variations in an object's weight on different celestial bodies.please give me examples to show your answer.Next you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law. Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU (2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5) Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU. A) Calculate a in AU. B) Convert your measurement of the moon's orbital period from days to years. C) By Newton's form of Kepler's third law, calculate the mass of the planet. D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.ASAP Please Assume that the planet is Earth. Thanks!
- Use Kepler's 3rd Law and the small angle approximation. a) An object is located in the solar system at a distance from the Sun equal to 41 AU's . What is the objects orbital period? b) An object seen in a telescope has an angular diameter equivalent to 41 (in units of arc seconds). What is its linear diameter if the object is 250 million km from you? Draw a labeled diagram of this situation.Using Kepler's 3rd law solve the following problem. Show your work and highlight your answer. In a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?A planet � moves in a circular orbit around a Star named planet of mass �! =2.7 × 10"# kg as shown in figure 2. The period of the orbit is 14 days. Derive a suitable mathematical formula to calculate the radius of the orbit.