If a sample of hydrogen gas was collected over water. If the total pressure was 135.5 KPa, what would be the pressure of the dry gas alone if you know that the pressure of water vapor is 2.8 KPa?* O 87.6 O 53.3 132.7 O 92.7

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A: According to ideal gas equation,  PV = nRT V = (nRT÷P) n = moles = (given mass ÷ molecular mass)