If an arrow is shot straight upward on the moon with a velocity of 61 m/s, its height (in meters) aftert seconds is given by S(t) = 61t -0.83t2.What is the velocity of the arrow (in m/s) after 9 seconds?After how many seconds will the arrow hit the moon?With what velocity (in m/s) will the arrow hit the moon?

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Asked Nov 1, 2019
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If an arrow is shot straight upward on the moon with a velocity of 61 m/s, its height (in meters) aftert seconds is given by S(t) = 61t -0.83t2.
What is the velocity of the arrow (in m/s) after 9 seconds?
After how many seconds will the arrow hit the moon?
With what velocity (in m/s) will the arrow hit the moon?
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If an arrow is shot straight upward on the moon with a velocity of 61 m/s, its height (in meters) aftert seconds is given by S(t) = 61t -0.83t2. What is the velocity of the arrow (in m/s) after 9 seconds? After how many seconds will the arrow hit the moon? With what velocity (in m/s) will the arrow hit the moon?

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Expert Answer

Step 1

Given, function is

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s(t) 61f-0.83r2 ..1)

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Step 2

Differentiate equation (1) with respect to ‘t’,

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d s6)=(61-083) ( 61t-0.83t2 dt s'(t)(61-1.66 (2)

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Step 3

Part (a): velocity of arrow...

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s'(9) (61-1.66x 9) s'(9)= 46.06 velocity of arrow after 9 seconds is 46.06 m/s

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Calculus

Derivative

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