If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resultingspeed? (e = 1.60 x 10-19 C, k= 1/4ne0 = 8.99 x 109 N. m2/C2, mel = 9.11 x 10-31 kg)%3DO 5.9 x 107 m/s2.9 x 107 m/sO 4.9 x 10 m/s3.9 x 10 m/sNone of the given choices.

Given Information:- Potential difference is ∆V=9.9 kV=9.9 kV×103 V1 kV=9.9×103 V Magnitude of charge…

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed? (e = 1.60 x 10-19 C, k= 1/4xe0 = 8.99 x 109 N• m2/C2, mel = 9.11 x 10-31 kg) 5.9 x 10 m/s 2.9 x 10 m/s O 4.9 x × 107 m/s 3.9 x 10 m/s O None of the given choices.

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed? (e = 1.60 x 10-19 C, k= 1/4xe0 = 8.99 x 109 N• m2/C2, mel = 9.11 x 10-31 kg) 5.9 x 10 m/s 2.9 x 10 m/s O 4.9 x × 107 m/s 3.9 x 10 m/s O None of the given choices.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 5OQ

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting
speed? (e = 1.60 x 10-19 C, k= 1/4ne0 = 8.99 x 109 N. m2/C2, mel = 9.11 x 10-31 kg)
%3D
O 5.9 x 107 m/s
2.9 x 107 m/s
O 4.9 x 10 m/s
3.9 x 10 m/s
None of the given choices.

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