If an express application contains the following call to getg: app.get('/foo', (req, res) => res.send ('bar')); Assuming that the application is running on port 3000 and that the browser has never accessed this path previously, what http response status code would be received by the browser if the browser requests http://localhost:3000/foo ..?
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- Assume that there is a function in a web application that allows users to change theircurrent email address to a new one.The following is an example of a HTTP POST request that will be sent to the vulnerableweb application when the user tries to perform email change action:POST usr/emailchange.php HTTP/1.1Host: example.comConnection: Keep-AliveCookie: session=abcwsdagePkBZzeR9hGhTlvxyHfsZf1The following is the parameter for the email in the POST request:Form Dataemail=example@utas.edu.au(a) Design an CSRF attack to exploit the existing vulnerability by creating an HTMLpage with the required method, URL, parameters and action to change the emailwhen the victim hits the URL of this webpage. Assume that there are no preventiontechniques implemented.(b) What will happen if the victim hits your code in (a) when he/she authenticatedalready?(c) What will happen if the victim hits your code in (a) when he/she not authenticatedalready?Using the xhr variable, initialize a connection to GET https://wp.zybooks.com/grades.php?name=Katie, set the response type to json, then send the request. function responseReceivedHandler() {console.log("Response received");} var xhr = new XMLHttpRequest();xhr.addEventListener("load", responseReceivedHandler);Modify the server code so that it prints the client’s IP and port number when it receive a new connection. from socket import * serverName = 'localhost' serverPort = 12000 clientSocket = socket(AF_INET, SOCK_STREAM) clientSocket.connect((serverName,serverPort)) sentence = input('Input lowercase sentence:') byteToSend = str.encode (sentence) clientSocket.send(byteToSend) modifiedSentence = clientSocket.recv(1024) print('From Server:', modifiedSentence) clientSocket.close() from socket import * serverPort = 12000 serverSocket = socket(AF_INET,SOCK_STREAM) serverSocket.bind(('',serverPort)) serverSocket.listen(1) print ('The server is ready to receive') while 1: connectionSocket, addr = serverSocket.accept() sentence = connectionSocket.recv(1024) capitalizedSentence = sentence.upper() connectionSocket.send(capitalizedSentence) connectionSocket.close() from socket import * serverName = 'localhost' serverPort = 12000 clientSocket = socket(AF_INET,…
- Which of the following constructor create a server socket with the specified port, listen backlog, and local IP address to bind? ServerSocket(int port) ServerSocket(int port, int backlog) ServerSocket(int port, int backlog, InetAddress bindAddr) ServerSocket()the nodejs server code is like this const http = require("http");const url = require('url'); var hostName = '127.0.0.1';var port = 3000; var server = http.createServer(function(req,res){res.setHeader('Content-Type','text/plain');const parsed = url.parse(req.url);const pathname = parsed['pathname'] const queryObject = url.parse(req.url,true).query;let queryValue = queryObject['name'] if(queryValue==null){queryValue=""} if (pathname=="/"){res.end("SUCCESS!")}else if (pathname=="/echo"){res.end("SUCCESS! echo")} else if (pathname=="/foxtrot/:name"){queryValue = queryObject['name'].toString()res.end("SUCCESS! Received "+queryValue+" via foxtrot")}else{res.end("FAILED! Fix your URL.")} }) server.listen(port,hostName,()=>{console.log(`Server running at http://${hostName}:${port}/`);}); ======================== when i enter http://localhost:3000/foxrot/kilo i hope it to run and display "SUCCESS! Received kilo via foxtrot" but it shows like the picture whats this problem ?how to fix this…Which JavaScript statement should you execute first to enable your program to send asynchronous requests to the server over HTTP? a. xhr.send(null); b. let myReq = XMLHttpRequest.open(); c. let myReq = new httpRequest(); d. let myReq = new XMLHttpRequest();
- There are two files, PingProgram.docx and GetHostByName.docx. PingProgram needs an IP address to work, and doesn’t use URLs, as per the example below. GetHostByName will return an IP address given a URL, also shown below. GetHostByName takes in a URL and a port number. Rewrite PingProgram to do the following: 1.Accept either a URL or an IP address as an input. 2.Ping the requested server 3 times instead of once. 3.Present all 3 round trip times, along with an average round trip time.Suppose a client sends an HTTP request message with the If-modified-since header. Sup- pose the object in a server has not changed since the last time a client retrieved the object. Then the server will send a response message with the status code: A. 200 OK B. 404 Not Found C. 304 Not Modified D. none of the aboveYou are examining an Apache server, and see the following configuration: <VirtualHost *:443>ServerName webserverDocumentRoot /var/www/webserverSSLEngine onSSLCertificateFile /etc/ssl/certs/webserver.crtSSLCertificateKeyFile /etc/ssl/private/webserver.key</VirtualHost> What would you expect the hostname of the computer to be?
- 1) Which of the following are HTTP Response headers? (There are multiple correct options. Please select all of them.) Group of answer choices a.Content-Type b.Set-Cookie c.User-Agent d.Accept e.Cookie 2) Suppose an HTTP response contains the status code 411. It indicates that Group of answer choices a.the requested resource has moved. b.request was processed successfully. c.there is some problem in the request. d.further action from the client is needed. e.an exception happened on the server. 3) Which of the following Java class can you use to write an image stored in memory to disk? Group of answer choices a.FileWriter b.File c.FileOutputStream d.ByteArrayOutputStreamAn attacker tries to do banner grabbing on a remote web server and executes the following command:$ nmap -sV hackme.com -p 80 He gets the following output:Starting Nmap 7.90 ( http://nmap.org ) at 2020-09-26 22:47 ESTNmap scan report for hackme.com (108.58.137.114)Host is up (0.048s latency).PORT STATE SERVICE VERSION80/tcp open http Apache httpdService detection performed. Please report any incorrect results at http://nmap.org/submit/.Nmap done: 1 IP address (1 host up) scanned in 7.36 seconds What did the hacker accomplish? nmap can’t retrieve the version number of any running remote service. The hacker successfully completed the banner grabbing. The hacker should have used nmap -O host.domain.com. The hacker failed to do banner grabbing as he didn’t get the version of the Apache web server.PLEASE LOOK AT MY QUESTION CAREFULLY ! PLEASE LOOK AT MY QUESTION CAREFULLY ! PLEASE LOOK AT MY QUESTION CAREFULLY ! the nodejs server code is like this const http = require("http");const url = require('url'); var hostName = '127.0.0.1';var port = 3000; var server = http.createServer(function(req,res){res.setHeader('Content-Type','text/plain');const parsed = url.parse(req.url);const pathname = parsed['pathname'] const queryObject = url.parse(req.url,true).query;let queryValue = queryObject['name'] if(queryValue==null){queryValue=""} if (pathname=="/"){res.end("SUCCESS!")}else if (pathname=="/echo"){res.end("SUCCESS! echo")} else if (pathname=="/foxtrot/:name"){queryValue = queryObject['name'].toString()res.end("SUCCESS! Received "+queryValue+" via foxtrot")}else{res.end("FAILED! Fix your URL.")} }) server.listen(port,hostName,()=>{console.log(`Server running at http://${hostName}:${port}/`);}); ======================== when i enter http://localhost:3000/foxrot/kilo i hope it…