Consider a short, 10-meter link, over which a sender can transmit at a rate  of 150 bits/sec in both directions. Suppose that packets containing data  are 100,000 bits long, and packets containing only control (e.g., ACK or  handshaking) are 200 bits long. Assume that N parallel connections each  get 1/N of the link bandwidth. Now consider the HTTP protocol, and suppose  that each downloaded object is 100 Kbits long, and that the initial downloaded  object contains 10 referenced objects from the same sender. Would parallel  downloads via parallel instances of non-persistent HTTP make sense in this  case? Now consider persistent HTTP. Do you expect significant gains over  the non-persistent case? Justify and explain your answer

Operations Research : Applications and Algorithms
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ISBN:9780534380588
Author:Wayne L. Winston
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Chapter20: Queuing Theory
Section20.10: Exponential Queues In Series And Open Queuing Networks
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Consider a short, 10-meter link, over which a sender can transmit at a rate 
of 150 bits/sec in both directions. Suppose that packets containing data 
are 100,000 bits long, and packets containing only control (e.g., ACK or 
handshaking) are 200 bits long. Assume that N parallel connections each 
get 1/N of the link bandwidth. Now consider the HTTP protocol, and suppose 
that each downloaded object is 100 Kbits long, and that the initial downloaded 
object contains 10 referenced objects from the same sender. Would parallel 
downloads via parallel instances of non-persistent HTTP make sense in this 
case? Now consider persistent HTTP. Do you expect significant gains over 
the non-persistent case? Justify and explain your answer

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Step 1

Computer Science homework question answer, step 1, image 1

total time for all  received objects is given by:

(200/150+Tp + 200/150 +Tp + 200/150+Tp + 100,000/150+ Tp )
+ (200/(150/10)+Tp + 200/(150/10) +Tp + 200/(150/10)+Tp + 100,000/(150/10)+ Tp )
= 7377 + 8*Tp (seconds)


Then consider persistent HTTP connection. The total time needed is give by:
(200/150+Tp + 200/150 +Tp + 200/150+Tp + 100,000/150+ Tp )
+ 10*(200/150+Tp + 100,000/150+ Tp )
=7351 + 24*Tp (seconds)


Assume  that propagation the speed of light/mediam is 300*106 m/sec, then Tp=10/(300*106)=0.03 microsec.

 here Tp is negligible compared with the  transmission delay.

 

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