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If Cov(x, y) = 0, that means: x and y are dependent. Option 2 f(x,y) = f₁(x)f2(y) Option 1 E(xy) = E(x) + E(y)

If Cov(x, y) = 0, that means: x and y are dependent. Option 2 f(x,y) = f₁(x)f2(y) Option 1 E(xy) = E(x) + E(y)

Elementary Geometry for College Students
Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter6: Circles
Section6.CT: Test
Problem 11CT: aIf HP=4, PJ=5, and PM=2, find LP. _ bIf HP=x+1, PJ=x1, LP=8, and PM=3, find x. _
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If Cov(x, y) = 0, that means: x and y are dependent. Option 2 f(x,y) = f₁(x)f2(y) Option 1 E(xy) = E(x) + E(y)
Transcribed Image Text:If Cov(x, y) = 0, that means: x and y are dependent. Option 2 f(x,y) = f₁(x)f2(y) Option 1 E(xy) = E(x) + E(y)
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