If d = 30 cm and the current in the wire is 50 A. find the magnitude of thedmagnetic field in Tesla at point X.hint: Magnitude means use the absolute value.Answer:A second wire also carries a current from this time from right to left belowpoint X.dThe direction of the magnetic field around the bottom wire will beAt the point of the X the magnetic field from only the bottom wire will point A long straight wire carries a current from left to right below point X.d.The direction of the magnetic field around the wire will beAt the point of the X the magnetic field will pointChoose the equation or equations that you will need to use to find the magnetic field at point X.Select one or more:a. B Field at the center of a loop: B = NHOL/2Rb. c = fA%3Dc. Mirror or Thin Lens Equation: 1/d, + 1/d; =1/f, h/h; = -d,/d¡d. Torque on a loop: t = NIABsinee. Force between current carrying wires separated by distance d: F = Holil2L/2ndf. Force on a current carrying wire: FBILsine%3Dg. Magnetic Force on a moving charge: F = qvBsine%3Dh. Magnetic Flux: 0 = BAcos0%3Di. Force on an object mass m moving in a circle of radius R: F = mv?/Rj. Doppler shift: f = f(1 ± u/c)

Since you have posted a question with a multiple sub parts, we will solve first three sub - parts…

If d = 30 cm and the current in the wire is 50 A. find the magnitude of the magnetic field in Tesla at point X. wwww wwww hint: Magnitude means use the absolute value. Answer: A second wire also carries a current from this time from right to left below point X. The direction of the magnetic field around the bottom wire will be d wwwwwwwwwwwwwwww At the point of the X the magnetic field from only the bottom wire will point

If d = 30 cm and the current in the wire is 50 A. find the magnitude of the magnetic field in Tesla at point X. wwww wwww hint: Magnitude means use the absolute value. Answer: A second wire also carries a current from this time from right to left below point X. The direction of the magnetic field around the bottom wire will be d wwwwwwwwwwwwwwww At the point of the X the magnetic field from only the bottom wire will point

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 7OQ

See similar textbooks

Similar questions

Figure CQ30.10 shows four permanent magnets, each having a hole through its center. Notice that the blue and yellow magnets are levitated above the red ones. (a) How does this levitation occur? (b) What purpose do the rods serve? (c) What can you say about the poles of the magnets from this observation? (d) If the blue magnet were inverted, what do you suppose would happen?
A very large parallel-plate capacitor has uniform charge per unit area + on the upper plate and on the lower plate. The plates are horizontal, and both move horizontally with speed v to the right. (a) What is the magnetic field between the plates? (b) What is the magnetic field just above or just below the plates? (c) What are the magnitude and direction of the magnetic force per unit area on the upper plate? (d) At what extrapolated speed v will the magnetic force on a plate balance the electric force on the plate? Suggestion: Use Amperes law and choose a path that closes between the plates of the capacitor.
(a) An oxygen16 ion with a mass at 2.661026kg travels at 5.00106m/s perpendicular to a 1.20T magnetic field, which makes it move in a circular arc with a 0.231-m radius. What positive charge is on the ion? (b) What is the radio of this charge to the charge of an electron? (c) Discuss why the radio found in (b) should be an integer.
Unreasonable results A charged particle having mass 6.641027kg (that of a helium atom) moving at 8.70105m/s perpendicular to a 1.50-T magnetic field travels in a circular path of radius 16.0 mm. (a) What is the charge of the particle? (b) What is unreasonable about this result? (c) Which assumptions are responsible?
Find the direction of the magnetic field acting on a positively charged particle moving in the various situations shown in Figure P28.3 if the direction of the magnetic force acting on it is as indicated. Figure P28.3
A current I flows around a wire bent into the shape of a square of side a. What is tire magnetic field at the point P that is a distance z above the center of the square (see the accompanying figure)?
An electron moving with a velocity v=(4.0i+3.0j+2.0k)106m/s enters a region where there is a uniform electric field and a uniform magnetic field. The magnetic field is given by v=(1.0i2.0j+4.0k)102T. If the electron travels through a region without being deflected, what is the electric field?
Review A proton is accelerated from rest through a 5.00-V potential difference. a. What is the protons speed after it has been accelerated? b. What is the maximum magnetic field that this proton produces at a point that is 1.00 m from the proton?
An electron in a TV CRT moves with a speed at 6.00107m/s, in a direction perpendicular to the Earth’s field, which has a strength of 5.00105T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a correction.)
(a) A 0.750-m-long section of cable carrying current to a car starter motor makes an angle at 60° with the Earth’s 5.00105-T field. What is the current when the wire experiences a force of 7.00103N ? (b) If you run the wire between the poles of a strong horseshoe magnet, subjecting 5.00 cm of it to a 1.75T field, what force is exerted on this segment of wire?
Explain why the magnetic field would not be unique (that is, not have a single value) at a point in space where magnetic field lines might cross. (Consider the direction of the field at such a point.)