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A: Mass of object (m) = 4 kg acceleration (a) = 5 ms2coefficient of kinetic friction (μk) = 0.25
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Q: 2. Find the tension in each of the three cables supporting the traffic light if it weighs 2.00 x 102…
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Q: A series of weights connected by very light cords are given an upward acceleration of 4.00 m/s2 by a…
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Q: Substituting, for the coefficient of kinetic friction, we find Mk = 0.25 3 6 X m m 2 10 n) ( 2 451…
A: Solution: Given: To perform the computation and find the value of coefficient of kinetic friction:…
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- A 25.0 kg box slides down a 40 degrees incline at a constant speed of 10.0 m/s. 1. What would a force diagram look like for this situation? 2. Use the right triangle trigonometry to determine the vector components of the gravitational force which acts parallel and parpendicular to the incline. 3. Determine the gravitational force acting on the box. Please solve this.A student's true weight is 407 N (magnitude), and apparent weight at a certain time is 515 N (magnitude). What is this student's acceleration at this time, in m/s2? Use g = 10.0 m/s2.A race car rounds a curve at 57 m/s. The radius of the curve is 434 m, and the car's mass is 630 kg. (Assume the car's speed remains constant. Take the radially inward direction to be positive. Indicate the direction with the sign of your answer.) (a) What is the car's (centripetal) acceleration?(b) What is it in g's? (enter value to 3 decimal places) (c) What is the centripetal force acting on the car?
- 9. SCALARS AND VECTORS: The figure below shows three forces F1, F2, and F3 acting on a point O. Calculate the resultant force. Here are the choices: 2.805 N 2.805 N 3.775 N 3.775 N 4.356 N 4.356 N 5.136 NFor part B (answer is 0.28m) can you draw where the perpendicular distance between 48N forces is? And also can you show me the equation for part B? Because for part A (answer is 13.44N) I used M = Fx • Dy Fx is 84 kN and Dy is 16cm. I’m confused that the answer key for part B uses M = Fy • Dx M= 13.44 N•M Fy= 48 N I’m probably misunderstanding Dx at part B. So can you fully explain this question. Thank you!!!At launch a rocket has a mass of 3.66×104 kg, and the thrust of the engines is 5.34×105 N. If the rocket is launched straight upwards from the surface of Earth, what is the initial acceleration of the rocket? Take upwards to be the positive direction. Express your answer in m/s2 to 3 significant figures. Use g=9.81 m/s2.
- Juan pushes a lawn mower with a force of 75 N holding the handle in such a way that it makes an angle of 60.0 ° with the horizontal. Remember to make the diagram and identify the vectors. 1. What are the horizontal and vertical components of the force? 2. The handle is lowered so that it makes an angle of 30.0o with the horizontal. What are the horizontal and vertical components of the force?pls answer 100% correctly thanks, A box hangs from two cables fastened to the ceiling. The cables make angles of 36 degrees and 33 degrees to the ceiling. The mass of the box is 82 kg. Determine the tension in each cable. Include a diagram showing the addition of the vectors.1. Two masses mA = 17.88kg and mB = 23.56kg are on inclined and are connected by a string as shown in Figure3. Find the acceleration and tension of the cord. [Ignore the masses of the (frictionless) pulley and the cord]
- I NEED HELP WITH PART D, PLEASE. A 42.0-kg child takes a ride on a Ferris wheel that rotates four times each minute and has a diameter of 26.0 m. (a) What is the centripetal acceleration of the child? magnitude 2.28 m/s2 direction toward the center of the path. (b) What force (magnitude and direction) does the seat exert on the child at the lowest point of the ride? magnitude 507.36N direction up toward the center (c) What force does the seat exert on the child at the highest point of the ride? magnitude 315.84N direction up away from the center (d) What force does the seat exert on the child when the child is halfway between the top and bottom? (Assume the Ferris wheel is rotating clockwise and the child is moving upward.) magnitude Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. N direction °…I NEED HELP WITH PART D, PLEASE. A 42.0-kg child takes a ride on a Ferris wheel that rotates four times each minute and has a diameter of 26.0 m. (a) What is the centripetal acceleration of the child? magnitude 2.28 m/s2 direction toward the center of the path. (b) What force (magnitude and direction) does the seat exert on the child at the lowest point of the ride? magnitude 507.36N direction up toward the center (c) What force does the seat exert on the child at the highest point of the ride? magnitude 315.84N direction up away from the center (d) What force does the seat exert on the child when the child is halfway between the top and bottom? (Assume the Ferris wheel is rotating clockwise and the child is moving upward.) magnitude Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. N direction °…15) Consider the three vectors shown below in the attache image. In this example, each vector represents a force in Newton’s (N). Each vector can be resolved into an x and y component. Resolve vector A into its x and y components. Round your answers to two decimal places. x component of vector A: _________________________________ y component of vector A: _________________________________ 16) Suppose Vishal goes for a long jog. During his journey: He travels 25 m east, Then 50 m at an angle of 40° N of E (North of East) Then 10 m North, Then 60 m at an angle of 30° S of W (South of West) Calculate Vishal’s displacement. Note: Specify the magnitude, angle, and reference of the displacement vector. Include all units with your answers and round your answers to two decimal places. Magnitude: _________________ Angle: ______________________ Reference: ______________________