If n = 12, I = 33, and s = 2, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to three decimal places. 0.354 Question Help: Message instructor Submit Question

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n=30, (x-bar)=38, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

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Q: If n-29, (x-bar)-35, and s-7, construct a confidence interval at a 90% confidence level. Assume the…

A: Givenn=29x=35s=7confidence interval = 90%

Q: A If n=21, ¯x (x-bar)=34, and s=8, construct a confidence interval at a 98% confidence level. Assume…

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Q: Construct the confidence interval for the population mean y. C=0.95, x= 16.7, o= 4.0, and n= 75. A…

A: Here, C=0.95, x=16.7, σ=4.0, and n=75.

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: If n=31, ¯xx¯(x-bar)=30, and s=10, construct a confidence interval at a 80% confidence level. Assume…

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Q: If n=14, (x-bar)=37, and s=7, construct a confidence interval at a 98% confidence level. Assume the…

A: Given,n=14x¯=37s=7degrees of freedom(df)=n-1df=14-1=13α=1-0.98=0.02α2=0.01t0.01(13)=2.650     (from…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: If n=28, a(x-bar)=36, and s=17, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 24, = 47, and s = 10, construct a confidence interval at a 98% confidence level. Assume the…

A: Sample mean = 47Sample size = 24Sample standard deviation = 1098% confidence level

Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=29,  x¯=30, and s=17, construct a confidence interval at a 99% confidence level. Assume the…

A: From the provided information, Sample size (n) = 29 Sample mean (x̅) = 30 Sample standard deviation…

Q: When alpha is set to 0.01 what is the confidence level ? answer choices : 0.01 0.02 0.98 0.99

A: From the provided information, Level of significance (α) = 0.01

Q: Use the following pairs of observations to construct an 80% and a 98% confidence interval for B,. 2…

A: Introduction: The response variable is y, and the explanatory variable is x.

Q: If n-28, 2(x-bar)-38, and s-13, construct a confidence interval at a 98% confidence level. Assume…

A: Given : Sample Size, n = 28 Sample Mean, x̄ = 38 sample standard…

Q: Which of the following would result in the narrowest confidence interval? A. 80% confidence level…

A: The narrowest confidence interval will result from larger sample size and a smaller confidence…

Q: If n=18, ¯x=x¯=34, and ss=15, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If all other factors are held constant, which confidence level will produce the smallest width for a…

A: Solution Decreasing the confidence level making the confidence interval Smaller.

Q: A​ 95% confidence interval for the proportion of U.S. adults who subscribe to some sort of streaming…

A: In the above question, we are given,  a confidence interval is

Q: Construct the 95% confidence interval estimate of the population proportion ? if the sample size is…

A: Given Data Sample Size, n = 400 Number of successes, x = 52.0 confidence level,c=…

Q: If n=25, ^-x=49, and s=5, construct a confidence interval at a 98% confidence level. Assume the data…

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Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: If n=18, (x-bar)=D43, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=22, ¯xx¯(x-bar)=38, and s=13, construct a confidence interval at a 80% confidence level. Assume…

A: The data provided is- x-bar = sample mean = m = 38 s = standard deviation = 13 n = sample mean = 22…

Q: Determine the confidence interval of the following: Given the information: the sampled population…

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Q: If n = 28, a = 38, and s = 17, construct a confidence interval at a 99% confidence level. Assume the…

A: As given: n =28 x¯=38 s = 17 It is asked to construct a confidence interval at a 99% confidence…

Q: If n-27, (x-bar)=42, and s-4, construct a confidence interval at a 99% confidence level. Assume the…

A: xbar=42  s=4 n=27

Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…

A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…

Q: If n=20, (x-bar)=47, and s=15, construct a confidence interval at a 99% confidence level. Assume the…

A: The sample size is 20, sample mean is 47, and sample standard deviation is 15. The degrees of…

Q: If n-31, (x-bar)=40, and s-5, construct a confidence interval at a 98% confidence level. Assume the…

A: Given that  Sample Mean \bar XXˉ = 4040 Sample Standard Deviation (s)(s) = 55 Sample Size…

Q: Select the correct response. a) Given the same sample data, the margin of error in a 90% confidence…

A: a) Given the same sample data, the margin of error in a 90% confidence interval would be smaller…

Q: Given the information: the sampled population is normally distributed, X– = 36.5, σ = 3, and n = 20.…

A: Given that

Q: If n=41, ¯x=39, and s=16, construct a confidence interval at a 99% confidence level. Assume the data…

A: Given that  Sample size (n) = 41 Sample mean (x¯) = 39 Sample standard deviation (s) = 16 Confidence…

Q: If n=21, (x-bar)=34, and s=8, construct a confidence interval at a 98% confidence level. Assume the…

A: Here, mean is 34 and standard deviation is 8. Sample number is 21. We will use one sample t…

Q: The t-value (t - score) that would be used to construct a 99% confidence interval given a sample…

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Q: Construct the confidence interval for the population mean μ   c=0.90 x=7.2, σ=0.6 , n=44 A 90%…

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Q: If n = 11,(x -bar)= 31, and s = 19, construct a confidence interval at a 99% confidence level.…

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Q: If n=n= 19, ¯xx¯ = 40, and s=s= 19, construct a confidence interval at a 80% confidence level.…

A: The sample size n is 19.

Q: In a survey, the planning value for the population proportion is p* = 0.25. How large a sample…

A: Given : Population proportion (p*) = 0.25 Confidence level = 95% So ; significance level (α) =…

Q: If n=28, ¯xx¯(x-bar)=42, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: Use the given confidence interval to find the point estimate ?̂p^.   0.14<?<0.84

A: Use the given confidence interval to find the point estimate ?̂p^.   0.14&lt;?&lt;0.84 The lower…

Q: . Find the length of the confidence interval, given the following data: s= 6.5, n = 15, confidence…

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Q: If n=11, 7(x-bar)=45, and s-5, construct a confidence interval at a 95% confidence level. Assume the…

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Q: If n=25, ¤=30, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…

A: It is given that sample mean is 30, sample size is 25 and the sample standard deviation is 7.

Q: If n=20, ¯xx¯(x-bar)=43, and s=10, construct a confidence interval at a 98% confidence level. Assume…

A: Here we need to compute a 98% confidence interval from the given information. Given sample size=20…

Q: When computing a confidence interval for the population mean µ when the population SD a is known,…

A: Given data: Confidence level = 85% Population standard deviation is known. To find: Critical value

Q: Which confidence level will produce the widest confidence interval, given a sample proportion of…

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Q: Use the given data to construct a 99% confidence interval for the population proportion p. x= 50,…

A: We have given that,  Sample size (n) = 70 and favorable cases (x)=50  Then,  We will find 99%…

Q: on the data she gathers. Which one of the following combinations of sample size and confidence level…

A: here AS PER GUIDELINES I HAVE CALCULATED FIRST MAIN QUESTION , AS YOU HAVE POSTED MULTIPLE DIFFRENT…