If the mantissa in a 16-bit floating point number is 10 bits long, then this mantissa 1001100000 when converted to base-10 is equal to: a) .52564 b) .59375 c) .54352 d) .56782 e) None among the given choices
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If the mantissa in a 16-bit floating point number is 10 bits long, then this mantissa 1001100000 when converted to base-10 is equal to:
a) .52564
b) .59375
c) .54352
d) .56782
e) None among the given choices
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- the following decimal numbers are stored in excess -50 floating point format, with the decimal point to the left of the first mantissa digit. A 9 is used as a negative sign. Perform the following calculations and present your result in standard decimal sign and magnitude notation.05115611 + 04712310Use the format SEEMMMM. All digits are decimal. The exponent is stored excess-50. The implied decimal point is at the beginning of the mantissa. The sign is 1 for a positive number, 7 for a negative number. Hint: Note carefully the number of digits in the mantissa! a. Convert the decimal number 28643 to floating point.b. What is the range of numbers that can be stored in this format? c. What is the floating-point representation for: −28569? d. What is the floating-point representation for 0.0000019557?Computer Science Help please. Only MIPS. Write a program that asks the user to enter an integer and outputs the integer in 32-bit two’s completement binary. There should be a space separating each 4 digits.
- 3. If the decimal point is placed to the right of the first significant digit, then the number is called as ________. a. Orthogonal b. Normalized c. Determinate d. None of the above1. Let x be the first two digits of your matric number (group leader), y be the last two digits of your matric number, and define z as x.y If the first digit of y is 0, replace it with 7. Example: Suppose your matric number is 2013104. Thus, x=20, y=74 and z=20.74 determine the IEEE-754 single precision floating-point numbers of decimal value x.y Explain each step.Assume our floating-point format is (decimal) X.XX * 10Y. Show the steps involved in floating point addition by using 6.11*101 + 5.76*103 as an example.