If the roots of a homogeneous DE with constant coefficients were: m1 = 0, m2= 3 & m3= 2 ± 3i ,what would the general solution be?A.y = Ce3x + C2e2*cos3x + C3e2*sin3xВ. у %3D Сі + Сде3х + Сзе2х сos3x + Cae2xsin3xC. y = C1 + C2e3* + Cze2*cos3xD. у %3DCe* + Cze3x + C3cos3x + C4sin3xE. None

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Answered: If the roots of a homogeneous DE with…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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If the roots of a homogeneous DE with constant coefficients were: m1= 0, m2 = 3 & m3 = 2 ± 3i , what would the general solution be? A. y = Ce3* + Cze2*cos3x + Cze2* sin3x B. y = C, + Cze3* + Cze2*cos3x + C4e2*sin3x C. y = C1 + Cze3× + Cze2*cos3x D. y = Ce* + Cze3* + C3cos3x + C4sin3x E. None

If the roots of a homogeneous DE with constant coefficients were: m1= 0, m2 = 3 & m3 = 2 ± 3i , what would the general solution be? A. y = Ce3* + Cze2cos3x + Cze2 sin3x B. y = C, + Cze3* + Cze2cos3x + C4e2sin3x C. y = C1 + Cze3× + Cze2cos3x D. y = Ce + Cze3* + C3cos3x + C4sin3x E. None