if user_tickets< 5: num_tickets=1 else: num_tickets= user_tickets
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user_tickets = int(input())
if user_tickets< 5:
num_tickets=1
else:
num_tickets= user_tickets
print('Value of num_tickets:', num_tickets)
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- Health application: BMI) Revise Listing 3.4, ComputeAndInterpretBMI.java, to let the user enter weight, feet, and inches. For example, if a person is 5 feet and 10 inches, you will enter 5 for feet and 10 for inches. Here is a sample run: Enter weight in pounds: 140 Enter feet: 5 Enter inches: 10 BMI is 20.087702275404553This is what I currently have : void displaySentence(char * sentence); char * sentence;int FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }
- Date Printer Write a program that reads a char array from the user containinga date in the form mm/dd/yyyy. It should print the date in the form March 12, 2014.ISBNThis problem is slightly more difficult than the above problem. This one requires a data type that stores 10 digits. BackgroundPublishers and bookstores use a number system called the International Standard Book Number (ISBN) system to identify books. At the start of publication, each book is assigned a unique ISBN. An ISBN, once assigned, can never be re-used. Click here for detailed information on this numbering system.An ISBN consists of exactly 10 digits. The rightmost digit is the check digit. The check digit is validated modulo 11.• multiply each digit from the first to the ninth by a weight from 10 to 2 respectively (the first digit by 10, the second by 9,.., the ninth by 2).• the sum of the products plus the check digit should be divisible without remainder by 11.• if there is a remainder, the whole number is not a valid ISBN SpecificationsDesign a program that validates an ISBN. Your program keeps accepting a whole number and determining if that whole number is a valid…def small_index(items: list[int]) -> int:"""Return the index of the first integer in items that is less than its index,or -1 if no such integer exists in items.>>> small_index([2, 5, 7, 99, 6])-1>>> small_index([-5, 8, 9, 16])0>>> small_index([5, 8, 9, 0, 1, 3])3"""
- 6. sum_highest_five This function takes a list of numbers, finds the five largest numbers in the list, and returns their sum. If the list of numbers contains fewer than five elements, raise a ValueError with whatever error message you like. Sample calls should look like: >>> sum_highest_five([10, 10, 10, 10, 10, 5, -17, 2, 3.1])50>>> sum_highest_five([5])Traceback (most recent call last): File "/usr/lib/python3.8/idlelib/run.py", line 559, in runcode exec(code, self.locals) File "<pyshell#44>", line 1, in <module> File "/homework/final.py", line 102, in sum_highest_five raise ValueError("need at least 5 numbers")ValueError: need at least 5 numbersTreasure Hunter description You are in front of a cave that has treasures. The cave canrepresented in a grid which has rows numbered from 1to , and of the columns numbered from 1 to . For this problem, define (?, )is the tile that is in the -th row and -column.There is a character in each tile, which indicates the type of that tile.Tiles can be floors, walls, or treasures that are sequentially representedwith the characters '.' (period), '#' (hashmark), and '*' (asterisk). You can passfloor and treasure tiles, but can't get past wall tiles.Initially, you are in a tile (??, ). You want to visit all the treasure squares, andtake the treasure. If you visit the treasure chest, then treasurewill be instantly taken, then the tile turns into a floor.In a move, if you are in a tile (?, ), then you can move tosquares immediately above (? 1, ), right (?, + 1), bottom (? + 1, ), and left (?, 1) of thecurrent plot. The tile you visit must not be off the grid, and must not be awall patch.Determine…Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. #include <iostream>using namespace std; int main() { const int NUM_POINTS = 4; int dataPoints[NUM_POINTS]; int controlValue; int i; cin >> controlValue; for (i = 0; i < NUM_POINTS; ++i) { cin >> dataPoints[i]; } /* Your solution goes here */ for (i = 0; i < NUM_POINTS; ++i) { cout << dataPoints[i] << " " ; } cout << endl; return 0;}
- Assign pizzasInStore's first element's caloriesInSlice with the value in pizzasInStore's second element's caloriesInSlice. Only the *your code goes here* can be affected, the rest of the program cannot be changed.Program below:--------------------------- #include <iostream>#include <vector>#include <string>using namespace std; struct PizzaInfo {string pizzaName;int caloriesInSlice;}; int main() {vector<PizzaInfo> pizzasInStore(2); cin >> pizzasInStore.at(0).pizzaName;cin >> pizzasInStore.at(0).caloriesInSlice; cin >> pizzasInStore.at(1).pizzaName;cin >> pizzasInStore.at(1).caloriesInSlice; /* Your code goes here */ cout << "A " << pizzasInStore.at(0).pizzaName << " slice contains " << pizzasInStore[0].caloriesInSlice << " calories." << endl;cout << "A " << pizzasInStore.at(1).pizzaName << " slice contains " << pizzasInStore[1].caloriesInSlice << " calories." <<…create a prog that will compute the final grade for a certain student and will display the final grade and a remark if it is passed or failedPass = 75 aboveFailed = 74 belowCS= 60% quiz + 40 assignmentPG =[ 2(Pcs) + PE] / 3TMG = [2(Mcs) +ME] /3MG = [2(TMG) + PG] / 3TFG = Fcs +ME + SFEFG = [2(TFG) + MG ] / 3sample output:enter name of student: Cruzenter quiz Score: 75enter assignment Score: 75enter PE Score: 75PG of Cruz is : 75enter Mquiz Score: 75enter Massignment Score: 75enter ME Score: 75MG of Cruz is: 75enter Fquiz Score: 75enter Fassignment Score: 75enter SFE Score: 75enter FE Score: 75MG of Cruz is: 75FG of Cruz is : 75congrats you PASSAssume that number is an int array and intptr is an int pointer. Which statement correctly assigns the address of the number array to the intptr pointer?• *intptr = &number;• intptr = &number;• intptr = *number;• intptr = number;