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- Not pseudocode Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]Create an algorithm that gives the formula that computes the numberof dots needed for a given input "layer". Assume that this can accommodate an “infinite” number of dots. Example:layer:1 dots: 1layer:2 dots: 3layer:3 dots:6code Connect6State.java according to the following instructions Class Connect6State java.lang.Object Connect6State public class Connect6State extends java.lang.Object Connect6State - A representation of a Connect6 (http://en.wikipedia.org/wiki/Connect6) game state. We assume a square grid board size specified to be a positive integer less than or equal to 26. Size 19 is common. The first and second players place pieces on the board that are black and white, respectively. Each piece is placed in an unoccupied grid position. On the first turn, the first player places one piece. Afterwards, players alternate placing two pieces per turn. Play continues until either one player completes a consecutive line of 6 or more of their pieces or no play is possible. The player with 6 or more pieces in a horizontal, vertical, or diagonal line is the winner. If no legal play is possible, the game is a draw. Field Summary Fields Modifier and Type Field Description static int…
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- - Can you provide me with the correct answer - The answer I inputted was 25,33,145,2 but it was shown as incorrect on my homework portal.use this link to simulate http://automatonsimulator.com/2. 1,2,3,...what? by CodeChum Admin I’m Dr. Frankenstein, and I’ve just created an intelligent monster! It can even count numbers now but the problem is, it can only count up to 3, so maybe it isn’t so intelligent after all. I want to use my creation to terrorize the villages but it keeps malfunctioning when it sees a digit that is greater than 3 so the villagers just put up signs of digits greater than 3. Make a program that is able to recognize digits greater than 3 so that it can avoid it or I'll have my monster terrorize YOU instead! Input 1. Integer n Description The integer to be processed. Constraints 0 <= n <= 2147483647 Sample 45 Output The first line will contain a message prompt to input the value of n. The succeeding line will contain all the digits of n that are greater than 3 and if there is none, the word "none". Enter · n : · 41545
- Create a java program that uses the Stack (lifo) to do the following in the attatched image. The program should repesent a bus service where the riders are getting on.JAVA PLEASE Write a block of code that displays an image of an animal from a URL.I want to add one green leaf on the right side of the flower how can I do this?? What should I add to my code for this? Thanks for help My code n=800;r=linspace(0,1,n);theta=linspace(0,2*pi,n);[R,THETA]=ndgrid(r,theta);% define the number of petals we want per cycle. Violets have 5!petalNum=5;x = 1 - (1/2)*((5/4)*(1 - mod(petalNum*THETA, 2*pi)/pi).^2 - 1/4).^2;% update the formula for phi to stop the spiralling effectphi = (pi/2)*exp(-2*pi/(8*pi));y = 1.95653*(R.^2).*(1.27689*R - 1).^2.*sin(phi);R2 = x.*(R.*sin(phi) + y.*cos(phi));X=R2.*sin(THETA);Y=R2.*cos(THETA);Z=x.*(R.*cos(phi)-y.*sin(phi));% color code for blueviolet RGB 138,43,226% Indigo rgb value (75,0,130)mapSize=20;blue_map=linspace(138,75,mapSize)';blue_map(:,2)=linspace(43,0,mapSize)';blue_map(:,3)=linspace(226,130,mapSize)';% and a pretty bit in the middlegold_map=[255 215 0; 250 210 0];% combine to form a full flower mapviolet_map=[gold_map; blue_map];% Now lets plot it and try and pick an attractive…